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Mumz [18]
3 years ago
10

How do you solve this question?

Mathematics
1 answer:
aliya0001 [1]3 years ago
8 0
We can use the quadratic formula to solve this problem.

\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

You've already listed the values for 'a', 'b', and 'c', so just plug them into the formula:

\sf x=\dfrac{-(-12)\pm\sqrt{(-12)^2-4(4)(9)}}{2(4)}

Simplify:

\sf x=\dfrac{12\pm\sqrt{144-4(4)(9)}}{8}

Multiply:

\sf x=\dfrac{12\pm\sqrt{144-144}}{8}

Subtract:

\sf x=\dfrac{12\pm\sqrt{0}}{8}

Take the square root:

\sf x=\dfrac{12\pm 0}{8}

It doesn't matter if you add or subtract something with 0, you'll end up with the same thing, so we have:

\sf x=\dfrac{12}{8}\rightarrow\boxed{\sf 1\dfrac{1}{2}}
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