Step-by-step explanation:
the area of a triangle is always
baseline × height / 2
where baseline and height are perpendicular (with a 90° angle) to each other.
it does not matter, if the height is inside or outside of the triangle.
so, in our case the area is
4×5/2 = 2×5 = 10 units²
The Greatest Common Factor (GCF) of 25, 5, 11 and 23, 52, 7 is 1, same with 22,3 and 23, 5 and 13, 193, 232.
Step-by-step explanation: |x − y| = 1, ok lets play as Alice, my number is y, and the bob number is x.
the condition says that x-y = 1 or x-y = -1.
so, if you know x, then y = 1 +y or y = y - 1. so you have two possibilities.
let's see two cases : first, let's suppose there are no code in the conversation. Then the only way of being shure of your number, is if one of them have the lowest positive number, so the other should have the next one. So if Bob have the number one, Alice knows for shure that she has the 2. Bob knows that she has a 2, but that means he could have a 1 or a 3, but when he sees that Alice is shure about her number, he knows that his number is the 1.
the second case is where the conversation may be a sort of code, saying a phrase x times and changing when x = the number of the other person, in this case, bob will have the 201 and alice the 202.
In the division rule you subtract the exponents<span> when </span>dividing<span> numbers with the same base. </span>One<span> rule for exponents is that exponents add when you have the same base. This works for any number x that you want to plug in except for x = </span>0<span>,because </span>0/0<span> is indeterminate (it is like dividing </span>zero<span> by </span>zero<span>). No matter what number we use when it is raised to the </span>zero power<span> it will always be </span>1.
I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
