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SCORPION-xisa [38]
3 years ago
13

7 (×+5) when × 10 I need help

Mathematics
1 answer:
Paladinen [302]3 years ago
8 0
Simply substitute the x in the equation with 10

7(x + 5)
7(10 + 5)
7(15)
105
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From the set (76, 77, 78), use substitution to determine which value of x makes the equation true
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Answer:

The answer is C.

Step-by-step explanation:

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3 years ago
What are the solutions to the equation?<br> 7x^3=28x
11Alexandr11 [23.1K]

7x³ = 28x is our equation. We want its solutions.

When you have x and different powers, set the whole thing equal to zero.

7x³ = 28x

7x³ - 28x = 0

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x (7x² - 28) = 0

As 7 is a factor of 7 and 28, it too can be factored out.

x (7) (x² - 4) = 0

We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.

x (7) (x - 2) (x + 2) = 0

Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.

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x - 2 = 0   ----> so x = 2   after adding 2 to both sides

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