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gayaneshka [121]
2 years ago
7

(0) a^2+За + За +9 Factorise

Mathematics
1 answer:
VashaNatasha [74]2 years ago
6 0

Answer:

a^2+6a+9

Step-by-step explanation:

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For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger
11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let <em>X</em> = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = p=\frac{1}{120}.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X </em>is:

P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...

In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419

6 0
3 years ago
The sum of five consecutive numbers is 700, what is the first number?
Feliz [49]

Answer:

The first number is 138.

Step-by-step explanation:

Let the first number be <em>x.</em>

<em />

Then since they are consecutive numbers, the second number will be (<em>x</em> + 1), the third (<em>x</em> + 2), the fourth (<em>x</em> + 3) and the fifth being (<em>x</em> + 4).

We are given that their sum is 700. Therefore:

x+(x+1)+(x+2)+(x+3)+(x+4)=700

Solve for <em>x</em>. Combine like terms:

5x+10=700

Subtract 10 from both sides:

5x=690

Divide both sides by five. Therefore:

x=138

The first number is 138.

5 0
3 years ago
Read 2 more answers
6. Active is an energy drink that claims to provide physical strength. To test this claim, the
katen-ka-za [31]

Answer:

D) The standard deviation of the residuals

Step-by-step explanation:

5 0
3 years ago
Fins the least number which should be added to 4100 to get a perfect square. also find the square root of the perfect square.
nadezda [96]

First do prime fraction of 273584. Then make pair of 2 ( same number ) . Then add the number which did not come in pair to the original number.

992

273584+992=274576

root 274576 = 524

524^2= 274576 = Answer

4 0
3 years ago
Read 2 more answers
If i travel 568 miles in 8 hours how many miles did i travel in one hour
Harrizon [31]
568 ÷ 8 = 71 miles in one hour
4 0
3 years ago
Read 2 more answers
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