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gayaneshka [121]
3 years ago
7

(0) a^2+За + За +9 Factorise

Mathematics
1 answer:
VashaNatasha [74]3 years ago
6 0

Answer:

a^2+6a+9

Step-by-step explanation:

You might be interested in
Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 7y = sin(x)
Elza [17]
The first thing we must do in this case is find the derivatives:
 y = a sin (x) + b cos (x)
 y '= a cos (x) - b sin (x)
 y '' = -a sin (x) - b cos (x)
 Substituting the values:
 (-a sin (x) - b cos (x)) + (a cos (x) - b sin (x)) - 7 (a sin (x) + b cos (x)) = sin (x)
 We rewrite:
 (-a sin (x) - b cos (x)) + (a cos (x) - b sin (x)) - 7 (a sin (x) + b cos (x)) = sin (x)
 sin (x) * (- a-b-7a) + cos (x) * (- b + a-7b) = sin (x)
 sin (x) * (- b-8a) + cos (x) * (a-8b) = sin (x)
 From here we get the system:
 -b-8a = 1
 a-8b = 0
 Whose solution is:
 a = -8 / 65
 b = -1 / 65
 Answer:
 
constants a and b are:
 
a = -8 / 65
 
b = -1 / 65
4 0
3 years ago
A polynomial P has zeros when x=0, x=-1/6 and x=-3 Whats could be the equation p?
erma4kov [3.2K]

Answer:

P(x) = x^{3} + \frac{19}{6} x^{2} + \frac{1}{2} x

Step-by-step explanation:

x(x + 1/6)(x + 3) = P

x(x^{2} + 3x + 1/6(x) + 1/2) = P

x (x^{2} + 19/6(x) + 1/2) = P

x^{3} + \frac{19}{6} x^{2} + \frac{1}{2} x = P(x)

4 0
2 years ago
Please show work and solve will mark as brainly
dolphi86 [110]

Answer:

4 hours

Step-by-step explanation:

63-35=28 28 divided by 7= 4

8 0
2 years ago
Read 2 more answers
If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"
seraphim [82]

Answer:

a + b + c = \pi \\  =  > c=  \pi - a - b \\  <  =  >  \tan(c)  =  \tan(\pi - a - b)  =  -\tan(a + b)

Step-by-step explanation:

we have:

\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

we also have:

\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

from (1)(2) => proven

5 0
3 years ago
Using the image below, where would the coordinates of point A be if the triangle was translated by ⟨x−4,y+3⟩?
Dennis_Churaev [7]

Answer:

(-9,4)

Step-by-step explanation:

so we are going to take the original coordinates (-5,1) and to the operation that the question wants us to do (x-4,y+3) by subsitituing the variables in so we get (-5-4,1+3)

Answer: (-9,4)

6 0
2 years ago
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