suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
It would be 100. Because let's say you had to round 25 to the nearest 10 it would be 30 because everything ending with 5 (example: 5 to nearest 10 would go to 10 65 to the nearest ten would go to 70) but anything lower then 5 goes to the lower number.
Answer:
Y = 27.
Step-by-step explanation:
40 - 13 = 27. If we check our math 13 +27 does equal 40 making the equation correct.
Answer:
416 is your answer!!!
Step-by-step explanation:
mak me brainliest and add me as a fiend
Answer:
-7/2 or -3.5
Step-by-step explanation:
Make the equation first
7x-1 = 5x-8
7 = -2x
-7/2 = x