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Stells [14]
3 years ago
6

how does a value that is greater than 100% of the original value or less than 1% of the original value compare to the original v

alue
Mathematics
1 answer:
Zolol [24]3 years ago
3 0
We cannot just use the same percent and get back to the original<span> amount because we </span>are <span>taking that percent of a different </span>value<span>.</span>
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Kierston needs to paint a wall of the youth center. She knows that 1 can of paint covers an area of 2.2 square meters. Kierston
Step2247 [10]

Answer:

See Explanation

Step-by-step explanation:

Given

1\ can = 2.2m^2

Required

Determine the number of cans for the wall

The dimension of the wall is not given. So, I will use the following assumed values:

Length=20m

Width = 44m

First, calculate the area of the wall

Area = Length * Width

Area = 20m * 44m

Area = 880m^2

If 1\ can = 2.2m^2

Then x = 880m^2

Cross Multiply:

x * 2.2m^2 = 1 * 880m^2

x * 2.2m^2 = 880m^2

x * 2.2 = 880

Make x the subject

x = \frac{880}{2.2}

x = 400

400 cans using the assume dimensions.

So, all you need to to is, get the original values and follow the same steps

4 0
3 years ago
2x = 4y + 8, x - 2y = 4
Evgen [1.6K]

Answer: x = 8, y = 2, coordinates (8,2)

Step-by-step explanation:

2x = 4y + 8 (divide by 2 to get value of x)

x = 2y + 4

(now substitute x into the second equation to find value of y)

2y + 4 - 2y = 4

2y - 2y = 4 - 4 (divide by 2 to get value of y)

y - y = 2 - 2

y = 2

Now plug in value of "y" to get value of "x".

x - 2(2) = 4

x - 4 = 4

x = 8

Coordinates (8,2)

3 0
2 years ago
PLS HELP!! RIGHT ANSWER GETS BRAINLIEST!! pls only answer if u know the answer 100% this is a test!
katrin2010 [14]

Answer:

It’s -2 and 0 AND also 2 and 4

Step-by-step explanation:

Good luck!

5 0
3 years ago
Cmon y'all i only have 3 more questions
Afina-wow [57]

1.25

the exponent is to the 6th because there are six zeros

4 0
3 years ago
Read 2 more answers
Principal root of 144
Alex Ar [27]
√144 = √12^2 = 12

=========================
6 0
3 years ago
Read 2 more answers
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