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Darina [25.2K]
3 years ago
9

Write an expression for a number that is 5 times greater than 2

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

Answer:

x = 5x > 2

or just 5x > 2 ya its that

Step-by-step explanation:

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Find the midpoint of the line segment joining the two points.<br> (1.8, -3.4) and (-0.4, 1.4)
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Answer:

(0.7, -1)

Step-by-step explanation:

To find the coordinates for the midpoint you add each coordinate together and divide by 2.

M = (\frac{1.8 - 0.4}{2},  \frac{-3.4 + 1.4}{2})

M = (\frac{1.4}{2}, \frac{-2}{2})

M = (0.7, -1)

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What is the value of AAA when we rewrite \left(\dfrac {6}{17}\right)^{9x}( 17 6 ​ ) 9x (, start fraction, 6, divided by, 17, end
sineoko [7]

We have been given an expression \left(\dfrac {6}{17}\right)^{9x}. We are asked to find the value of A when rewrite our given expression as A^{x}.

To solve our given problem, we will use exponent properties.

Using exponent property a^{mn}=(a^m)^n, we can rewrite our given expression as:

\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}

Now, we will compare our expression with  A^{x}.

Upon comparing \left(\left(\dfrac {6}{17}\right)^9\right)^{x} with A^{x}, we can see that A=\left(\dfrac {6}{17}\right)^9.

Therefore, the value of A is \left(\dfrac {6}{17}\right)^9.

We can further simplify \left(\dfrac {6}{17}\right)^9 as:

\left(\dfrac {6}{17}\right)^9=\frac {6^9}{17^9}=\frac{10077696}{118587876497}

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