Answer:
All numbers less than 2 or ![(-\infty, 1]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%201%5D)
or 
Step-by-step explanation:
Given that:
Number is added to itself is less than the number subtracted from 6.
To find:
All such numbers.
Solution:
Let the number be 
.
Here, an inequality will be made.
When solved, it might give more than one answers.
As per the question statement, let us write the inequality.
Number added to itself 
Number subtracted from six = 
As per question:
So, the answer is:
All numbers less than 2 or or .
B.
Let's simply look at each conjecture and determine if it's true or false.
A. 2n– 1 is odd if n is positive: Since n is an integer, 2n will
always be even. And an even number minus 1 is always odd. Doesn't matter
if n is positive or not. So this conjecture is true.
B. 2n– 1 is always even: Once again, 2n will always be even. So 2n-1 will always be odd. This conjecture is false.
C. 2n– 1 is odd if n is even: 2n is always even, so 2n-1 will always
be odd, regardless of what n is. So this conjecture is true.
D. 2n– 1 is always odd: 2n will always be even. So 2n-1 will always be odd. Once again, this conjecture is true.
Of the 4 conjectures above, only conjecture B is false. So the answer is B.
Answer:
20) yes
21) -1
22) 1
23) -4
Step-by-step explanation:
Y = -3x + 13
Steps and the graph are on paper
Simplifying
2x + -3(3 * 0.6x + 2.7)
Multiply 3 * 0.6
2x + -3(1.8x + 2.7)
Reorder the terms:
2x + -3(2.7 + 1.8x)
2x + (2.7 * -3 + 1.8x * -3)
2x + (-8.1 + -5.4x)
Reorder the terms:
-8.1 + 2x + -5.4x
Combine like terms: 2x + -5.4x = -3.4x
-8.1 + -3.4x
