<span>f (n + 1) = f(n) + 2 so c is the answer
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F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
267.05 hope this helpssss
Answer:
This uses the method of elimination/addition.
Step-by-step explanation:
1 (9x + 7y = 15)
-7 (5x + y = -9) <— let’s eliminate y for both equations
9x + 7y = 15
+ -35x - 7y = 63 <— add both of the equations
—————————————————
- 26x + 0y = 6
(Please let me know if the answer is correct or not)
Answer:
3/4 i believe
Step-by-step explanation:
