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3 years ago

There are 12 people having lunch.Each person wants 1/3 of a sub sandwich.How many whole sub sandwiches are needed?

1 answer:

6 0

Each sub will feed 3 people if they split it by 1/3
take 12 and divide by 3
12/3= 4
they'll need 4 whole subs to feed 12 people

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Compare 2/5 and 1/10 use common denominator

enyata [817]

What i got was that 2/5 is greater 1/10 but it can also be 4/10>1/10 or 2/5>1/10

5 0

3 years ago

Ilean works as a welder and web designer. As a welder, she earns $18 per hour. Last week she worked 푥 hours as a welder and her

trapecia [35]

The expression that represent the total amount Ilean earned last week is 27(18) + 75

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let y represent the total amount Ilean earned last week for working x hours.

Since she worked for 27 hours and earned $75 to design a web page. Hence:

y = 27(18) + 75

The expression that represent the total amount Ilean earned last week is 27(18) + 75

Find out more on equation at: brainly.com/question/2972832

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8 0

2 years ago

Of the girls on the Alden Middle School soccer team, % also play on a travel team. How many of the girls on the middle school te

Wewaii [24]

Answer:

The question is incomplete, so I looked for similar ones and found:

<em>Of the 25 girls on the Alden Middle School soccer team, 40% also play on a travel team. How many of the girls on the middle school team also play on a travel team? </em>

we can solve this the following way:

25 girls on the soccer team x 40% that play on a travel team = 10 girls form the soccer team that play on a travel team

we can also multiply (25 girls x 40) / 100 = 10 girls

we can check our work by:

10 girls / 40% = 25 girls in total

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=x_%7B123%7D%20x%5E%7B2%7D" id="TexFormula1" title="x_{123} x^{2}" alt="x_{123} x^{2}" align="a

Vikentia [17]

Multiply x123 by x2 by adding the exponents x125

4 0

3 years ago

Read 2 more answers

Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for stro

tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation

n=2700 represent the random sample taken

X represent the people in England who are deficient in Vitamin D

$\hat p=0.2$ estimated proportion of England people who are deficient in Vitamin D

$\alpha=0.02$ represent the significance level

Confidence =0.98 or 98%

z would represent the statistic (variable of interest)

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.33$

And replacing into the confidence interval formula we got:

$0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182$

$0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218$

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

3 0

3 years ago