Ratios equivalent to 5:1 are
10:2
15:3
Answer:
P(x) = x^4 -16x^3 +76x^2 -72x -100
Step-by-step explanation:
The two roots 1-√3 and 1+√3 give rise to the quadratic factor ...
... (x -(1-√3))(x -(1+√3)) = (x-1)^2 -(√3)^2 = x^2 -2x -2
The complex root 7-i has a conjugate that is also a root. These two roots give rise to the quadratic factor ...
... (x -(7 -i))(x -(7 +i)) = (x-7)^2 -(i)^2 = x^2 -14x +50
The product of these two quadratic factors is ...
... P(x) = (x^2 -2x -2)(x^2 -14x +50) = x^4 +x^3(-14 -2) +x^2(50 +28 -2) +x(-100+28) -100
... P(x) = x^4 -16x^3 +76x^2 -72x -100
Answer:
4 and 4
Step-by-step explanation:
Method A
1) Method A: Let 2 be the starting point and -2, the finishing one. Counting between 2 and -2, we can count a distance of 4 units. That's the simplest way, but not convenient to great numbers on the Number Line.
Method B:
There is no such thing as a negative distance, as a physical quantity. So this is the reason why we need to compute the absolute value of two numbers, which is simply what was done on Method B.
|2-(-2)|=|4|=4
As we are dealing with absolute values, the order is not relevant after all, the result remains the same. Take a look:
|-2-2|=|-4|=4
That's why the greater (2) or the lesser number (-2) can be the subtrahend (in bold within the brackets.
Answer:
r = 3
Step-by-step explanation:
x^2 + 6x + y^2 - 8y = - 16
Take half the linear term and square it.
x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16
Add the squared amounts to the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16
Combine on the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = 9
Represent the 2 quadratics as perfect squares.
(x + 3)^2 + y - 4)^2 = 9
The radius is the square root of 9 which is 3
