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evablogger [386]
4 years ago
10

Find the domain and range, and compare it with the function y=1/x

Mathematics
1 answer:
siniylev [52]4 years ago
8 0
F(x) = 1/x and g(x) = -10/x

Domain:  same:  all real numbers other than x=0.
Range:  strictly speaking, these 2 functions have the same range:  all real numbers other than y=0.  But the graph of g(x) = -10/x looks stretched vertically when compared with that of f(x) = 1/x.
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What are the rules to remember when dividing fractions?
harkovskaia [24]

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copy the first fraction, turn the division sign to a multiplication sign and flip the second fraction

Step-by-step explanation:

ex: 2/5 divided by 1/4

turn it to- 2/5 x 4/1

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kow [346]

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Step-by-step explanation:

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An outdoor spigot at the school has a leak and is dripping water. A student counted eighty drops of water in five minutes and no
lianna [129]

Answer:

D. 108 liters

Step-by-step explanation:

Given that the leak is ;

5 drops = 5 minutes

?= 4 weeks

Find number of hours in 4 weeks

1 week=7days

4 weeks=?--------------cross multiply

4×7=28 days

1 day=24 hours

28 days=?--------------cross multiply

28×24=672 hours

Hour= 60 minutes

672 hours=?

672×60=40320 minutes

Finding the leakage in 4 weeks

80 drops= 5 minutes

?=40320 minutes------------cross multiplication

(40320×80)÷5 =645120 drops

Finding the liters of water wasted in 4 weeks

60 drops of water= 10 milliliters

645120 drops of water=?-------------cross multiply

(645120×10)÷60 =107520 milliliters

But you know

1 milliliter=0.001 liters

107520 milliliters=?-----------cross multiply

107520×0.001

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5 0
3 years ago
630 + 0 is greater than or is is less than630​
grigory [225]

Answer:

630+0 is 630. So 630 is equal to 630.

6 0
3 years ago
Need Help Asap and No Plagiarism Please Really Important need to pass. Look at the picture for question and answer A,B and C. (
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Answer:

This is an exponential growth equation of the form:

f(t) = A*(r)^t

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A is the initial quantity of something, suppose that is the population of some kind of animal

r is the rate of growth

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f(t) is the population of the animal at the time t.

For this question, we have the equation:

b(t) = 1200*(1.8)^t

And this represents the population of a kind of bacteria as a function of time.

a) 1200 is the initial population of the bacteria.

b) the 1.8 is the rate of growth.

c) Now we have the equation:

b(t) = 1000*(1.8)^t

In this case, 1000 will represent the initial population of bacteria for this second study.

And the difference between the 1200 for the first study, and the 1000 for this second study, means that for the first study the initial population of bacteria was larger. (200 units larger).

8 0
3 years ago
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