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3 years ago

7

Point I is on line segment HJ. Given I J equals 3X +3, HI equals 3X-1, and HJ equals 3X +8, determine the numerical length of HJ

.

2 answers:

Nezavi [6.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

3x + 3 + 3x - 1 = 3x + 8

6x + 2 = 3x + 8

3x + 2 = 8

3x = 6

x = 2

HJ= 3(2) + 8 =6 + 8 = 14

HI= 3(2) - 1 = 6 - 1 = 5

IJ = 3(2) + 3 = 6 + 3 = 9

Salsk061 [2.6K]3 years ago

4 0

Answer:14

Step-by-step explanation:

3x + 3 + 3x - 1 = 3x + 8

6x + 2 = 3x + 8

3x + 2 = 8

3x = 6

x = 2

HJ= 3(2) + 8 =6 + 8 = 14

HI= 3(2) - 1 = 6 - 1 = 5

IJ = 3(2) + 3 = 6 + 3 = 9

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Read 2 more answers

What is the solution to 3 times the square root of 4 minus 2 times the square root of 4? A. 0 B. 1 C. 2 D. 3

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For this case we have the expression:

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$\sqrt {4}$

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$3 \sqrt {4} -2 \sqrt {4} =$

They are similar terms, we can subtract:

$3 \sqrt {4} -2 \sqrt {4} = \sqrt {4} = \sqrt {2 ^ 2}$

By definition of power properties we have that:

$\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a$

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3 years ago