The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
Since opposite sides of parallelogram are equal therefore
9r-6=8r+3
r=9
EF=4r+19{opposite sides of parallelogram are equal}
=4×9+19
36+19
=55
Here is you answer.
Step-by-step explanation:
4,550 is the answer when you multiply the two numbers together.
Answer:
C
Step-by-step explanation:
Answer:
6x + 25 ≤ 135
Step-by-step explanation:
Maximum amount to spend = $135
Boxes of popcorn = 2
Boxes of candy = 3
Cost per box of popcorn = $6
For 3 boxes = $6 * 3 = $18
Cost per box of candy = $3.50
For 2 boxes = $2 * 3.50 = $7
Item cost = Cost of candy and popcorn = $18 + $7 = $25
Ticket price = $6
Inequality to find number of friends ;
Let number of friends = x
Ticket cost = 6x
Hence ;
Ticket cost + item cost ≤ 135
6x + 25 ≤ 135
