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1 year ago

13

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1 answer:

mixas84 [53]1 year ago

6 0

Answer:

$19

Step-by-step explanation:

56x9=504

523-504=19

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In a triangle RSTV, RS=5.3cm and ST=4.1 find perimeter of RSTV

Luba_88 [7]

Is that a with 4 vertices ,,,check your question

7 0

3 years ago

The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct

lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

$y=\dfrac{x}{1+x}$

Point $P\left(1,\dfrac{1}{2}\right)$ lies on the curve.

Point $Q\left(x,\dfrac{x}{1+x}\right)$ is an arbitrary point on the curve.

The slope of the secant line PQ is

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]$

1. If x=0.5, then the slope is

$\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333$

2. If x=0.9, then the slope is

$\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632$

3. If x=0.99, then the slope is

$\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513$

4. If x=0.999, then the slope is

$\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501$

5. If x=1.5, then the slope is

$\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2$

6. If x=1.1, then the slope is

$\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381$

7. If x=1.01, then the slope is

$\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488$

8. If x=1.001, then the slope is

$\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499$

7 0

3 years ago

Tanya [424]

Answer:

44 degrees

Step-by-step explanation:

if BAC and DAE are complementary then their sum is equal to 90 degrees

90 - 36 = 44 degrees

5 0

3 years ago

Read 2 more answers

Alyssa spent 9.20 for 16 packs of gum at this rate how much would it cost alyssa to buy 30 packs of gum.

zhuklara [117]

$17.25. Divide 9.20 by 16 and mulitply by 30.

6 0

3 years ago

Read 2 more answers

If f(x) = 1/9 x - 2, what is f-1 (x)

Snowcat [4.5K]

$f(x) = \frac{1}{9} x - 2 \\$

$f( - 1) = \frac{1}{9} ( - 1) - 2 \\$

$f( - 1) = - \frac{1}{9} - 2 \\$

$f( - 1) = - \frac{1}{9} - \frac{18}{9} \\$

$f( - 1) = - \frac{19}{9} \\$

6 0

3 years ago