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2 years ago

What fraction does each month have of a year

1 answer:

8 0

Hello,

Okay there are 12 months so that is the denominator and each month counts as one so that is the numerator. So the fraction would be 1/12.

Hope I Helped ;)

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Drag each title to the correct box. Not all tiles will be used

mestny [16]

Answer:

4, 1, 6.

See explanation

Step-by-step explanation:

You are given the equation

$d=vt-\dfrac{1}{2}at^2$

First subtract $vt$ from both sides:

$d-vt--\dfrac{1}{2}at^2$

and multiply the equation by -1:

$vt-d=\dfrac{1}{2}at^2\ \ \ \ (1)$

Now multiply (1) by 2:

$2(vt-d)=at^2\ \ \ \ \ (2)$

At last, divide by $a$

$t^2=\dfrac{2(vt-d)}{a}\ \ \ \ \ (3)$

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2 years ago

7/19 en numero decimal

Nataly [62]

Answer: 0.368421053

Step-by-step explanation: 19/7=0.368412053 :-)

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2 years ago

What is the slope of this line?

olga2289 [7]

Answer:

Step-by-step explanation:

In the Slope-Intercept Formula, y = mx + b, m is the Rate of Change [Slope]. Anyway, starting from the y-intercept of [0, 2], move 3 units north over 1 unit east. That is called rise\run → 3\1 = 3.

I am joyous to assist you anytime.

7 0

2 years ago

Read 2 more answers

In a survey of 300 college graduates 53 reported that they entered a profession closely related to their college major. if 9 of

bija089 [108]

Answer:

what are the choices?

Step-by-step explanation:

3 0

2 years ago

According to a recent publication, the mean price of new mobile homes is $63 comma 800. Assume a standard deviation of $7900.

wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,580, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,117, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}$

For n=25 we have:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580$

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117$

4 0

3 years ago