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Shalnov [3]
4 years ago
6

If the sphere shown above has a radius of 19 units, then what is the approximate volume of the sphere?

Mathematics
1 answer:
Maru [420]4 years ago
5 0
V ≈ 28730.91Hope this helps
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Given quadrilateral RSTU, determine if each pair of sides (if any) are parallel and which are perpendicular for the
-BARSIC- [3]

Answer:

US is parallel to RT, and UR is parallel to ST

ST is perpendicular to US and UR is perpendicular to RT

Basically anywhere that there's lines that make right angles are perpendicular to each other

I hope this helps

Step-by-step explanation:

4 0
4 years ago
What number goes in the box to make the equation true? Blank = 5/16 x 8/15
Sidana [21]

Answer:

The blank box is 1/6

Step-by-step explanation:

5/ 16 x 8/15 = 40/240

40/240 simplified = 1/6

3 0
3 years ago
Read 2 more answers
100 POINTS
olga nikolaevna [1]

Answer:

5.2

Step-by-step explanation:

To find the height of the plant after 7 weeks, we need to find out the equation of the line of best fit and plug in 7 for x. We already have our y - intercept, which is 1,  and we have a point on the x axis for which the y coordinate is an integer, (5, 4). Since we already have the y - intercept of +1 we have y = mx + 1. Since this applies to (5,4) we can plug this in to our equation. This is then 4 = 5m + 1. Subtracting 1 from both sides, we get 3 = 5m. Dividing by 5, we receive m = 3/5. Since now we have our slope, we can plug in 7 and find out our answer. Plugging in 7 we receive, y = 3/5 * 7 + 1, which is equal to y = 4.2 + 1. This means that y = 5.2, so 5.2 is our answer.

6 0
3 years ago
Read 2 more answers
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

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3 years ago
Comparing to Internet service plans plan one cost $34.99 per month plan to cost $134.97 every three months if Crystal plans to s
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Plan 1 because she spends 435.88 more if she goes with plan 2
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