Ask question

Ask question

All categories

2 years ago

9

Which of the following tables is a relation that represents a function?

1 answer:

uysha [10]2 years ago

3 0

The first one is not a function due to the rule that there can not be more than one x, such as there is a repeated number 1 , 2 , 1 , 4 There should not be two
x = 1 terms.

Same the same rule applies to the second option as well as the last.

Your answer is C. or the third option
x= 6, 5, 4, 1
y=6, 4, 6, 2

Hope this Helps

You might be interested in

An equation that shows the relationship of 30% of x is 40

Tresset [83]

What do you mean? Try to explain

5 0

2 years ago

Read 2 more answers

If f(x) = x 2 + 1, find f(a + 1). a 2+ 2 a + 2 a 2 + 2 a 2+ a + 1

goblinko [34]

2a+3

Step-by-step explanation:

5 0

2 years ago

I literally don’t get none of this

faust18 [17]

Answer:

Angle 5, 4, and 7.

Step-by-step explanation:

Angle 2 is vertical to angle 5, making them congruent.

Angle 2 corresponds with angle 4, making them congruent.

Angle 2 is an alternate interior to angle 7, making them congruent.

]

The rest of the angles just combine with angle two to make 180.

5 0

3 years ago

Use the distributive property to factor the expression.<br><br> 15x + 6

Marianna [84]

Take 3 out of both of them
3(5x+2)

5 0

3 years ago

See attached picture

yanalaym [24]

Answer:

$\frac{f(x+h)-f(x)}{h}$ $=2x + h$

Step-by-step explanation:

Given

$f(x)= x^2 + 2$

Required

Determine: $\frac{f(x+h)-f(x)}{h}$

First, we calculate f(x + h)

$f(x)= x^2 + 2$

$f(x+h) = (x+h)^2+2$

$f(x+h) = x^2+2xh+h^2+2$

So, we have:

$\frac{f(x+h)-f(x)}{h}$ $= \frac{x^2 + 2xh + h^2 + 2 - x^2 - 2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $= \frac{x^2 - x^2+ 2xh + h^2 + 2 - 2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $= \frac{2xh + h^2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $=2x + h$

8 0

2 years ago