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3 years ago

How do i do solve this math problem?

Mathematics

2 answers:

erica [24]3 years ago

5 0

-3*5*7=-105
When a square root of an a expression is multiples by itself the result is that expression.

mestny [16]3 years ago

4 0

When you multiply two square roots together, you basically multiply the numbers within and put a squre root over that.

For example, in this case:

sqrt (5) * sqrt (5) = sqrt (25) = 5

Now that we have 5, we just multiply that to -3 and 7:

5 * -3 * 7 = -105

The answer is -105.

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so Length(4) x Width(6) = 24

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3 years ago

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4 years ago

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

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$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

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7 0

3 years ago

Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a

Vitek1552 [10]

Answer:

$2ab - 6a + 5b - 15$

Step-by-step explanation:

Given

$2ab - 6a + 5b + \_$

Required

Fill in the gap to produce the product of linear expressions

$2ab - 6a + 5b + \_$

Split to 2

$(2ab - 6a) + (5b + \_)$

Factorize the first bracket

$2a(b - 3) + (5b + \_)$

Represent the _ with X

$2a(b - 3) + (5b + X)$

Factorize the second bracket

$2a(b - 3) + 5(b + \frac{X}{5})$

To result in a linear expression, then the following condition must be satisfied;

$b - 3 = b + \frac{X}{5}$

Subtract b from both sides

$b - b- 3 = b - b+ \frac{X}{5}$

$- 3 = \frac{X}{5}$

Multiply both sides by 5

$- 3 * 5 = \frac{X}{5} * 5$

$X = -15$

Substitute -15 for X in $2a(b - 3) + 5(b + \frac{X}{5})$

$2a(b - 3) + 5(b + \frac{-15}{5})$

$2a(b - 3) + 5(b - \frac{15}{5})$

$2a(b - 3) + 5(b - 3)$

$(2a + 5)(b - 3)$

The two linear expressions are $(2a+ 5)$ and $(b - 3)$

Their product will result in $2ab - 6a + 5b - 15$

Hence, the constant is -15

3 0

3 years ago