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Arte-miy333 [17]
2 years ago
14

Here are 5 red marbles, 8 blue marbles, and 12 green marbles in a bag.

Mathematics
2 answers:
natima [27]2 years ago
8 0

Answer:

5/25

Step-by-step explanation:

first you count how many there are which is 25 and than you 5 red marbles so it would be 5/25

Leviafan [203]2 years ago
7 0

Answer:

Probability of randomly drawing a red marble is [\frac{1}{5}

Step-by-step explanation:

Given 5 red marbles, 8 blue marbles, and 12 green marbles in a bag. we have to find the 5 red marbles, 8 blue marbles, and 12 green marbles in a bag.

As Probability of an event  is the chances of an event to occur. It is defined as the favourable outcomes by total number of outcomes.

As no. of red marbles are 5 and

Total number of marbles are 5+8+12=25 marbles.

Hence, probability of randomly drawing a red marble is

\frac{\text{Favourable outcomes}}{\text{Total number of outcomes}}=\frac{5}{25}=\frac{1}{5}

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Which expression is equivalent to -16 - 7?
alexandr1967 [171]

Answer:

- 16 + ( - 7 )

Step-by-step explanation:

- 16 + ( - 7 ) is same as - 16 - 7.

3 0
2 years ago
A 100-meter-long christmas train needs 30 seconds to cross a 400-meter-long bridge. assuming the train goes at a steady speed, h
san4es73 [151]
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2 years ago
Bailey tossed a coin 10 times. the results were 7 heads and 3 tails. What is the best comparison between the theoretical and exp
erastova [34]

Answer:

3/10

Step-by-step explanation:

i answered it already

8 0
3 years ago
Help is needed :) not sure what to do?
myrzilka [38]
The answer to the question is d
8 0
2 years ago
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Alexxandr [17]
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical. 
First, lets factor 8:
8=2 ^{3}
Now we can divide the power of the term, 3, by the index of the radical 2:
\frac{3}{2} = 1 with a remainder of 1
Next, lets do the same for our second term x^{7}:
\frac{7}{2} = 3 with a remainder of 1
Again, lets do the same for our third term y^{8}:
\frac{8}{2} =4 with no remainder, so this term will come out completely.

Finally, lets take our terms out of the radical:
\sqrt{8x^{7} y^{8}  }= \sqrt{ 2^{3} x^{7} y^{8}   }  =2 x^{3}  y^{4}  \sqrt{2x}

We can conclude that the correct answer is the third one. 

4 0
2 years ago
Read 2 more answers
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