Answer:
Step-by-step explanation:
Arc(AB) = 102 degrees
Arc(ADB) = 360 - 102 = 258
9514 1404 393
Answer:
1
Step-by-step explanation:

What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
9514 1404 393
Answer:
Step-by-step explanation:
You know the linear pair z° and 105° are supplementary angles, so ...
z = 180 -105 = 75
The other base angle of the isosceles triangle has the same measure, 75°. __
Then x can be found either from the sum of interior angles of the triangle, or from the relation of 105° to the "remote interior angles". The first relation gives ...
75° +75° +x° = 180° ⇒ x = 180 -150 = 30
The second relation gives ...
75° +x° = 105° ⇒ x = 105 -75 = 30
__
y° is supplementary to the left-side base angle, so is ...
y = 180 -75 = 105
Of course, you could also figure y from the symmetry of the figure.
The values of x, y, z are 30, 105, 75, respectively.
Answer:
a. is 1 and b is 2 and c is 3 I did it in algebra pay attention in class