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Tanzania [10]
2 years ago
10

Urgenttttt please I need it fast​

Mathematics
1 answer:
dolphi86 [110]2 years ago
5 0

Answer:

Below in bold.

Step-by-step explanation:

c) 3 x (9^2)^3/4 x ((81^3)^5/6

= 3 x 81^3/4 x 81^15/6

= 3 x 81^(3/4 + 15/6)

= 3 x 81^13/4

= 3 x 3^13

= 3^14

= 4,782,969.

f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2

=  5^-2 x^2y^-4 / 625 x^4y^-2

=  5^-2 x^-2 y^-2 / 5^4

= 5^-6 x^-2y^-2

= 0.000064x^-2y^-2.

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Find the unknown side length of the rectangle is 3 2/3 and if the area is 11m2
patriot [66]

Answer:

The width of the rectangle given is equal to 3m.

Step-by-step explanation:

In order to solve this question we need to know that the areas of the rectangle is equal to A_{rectangle} = (l)(w), where "l" is length and "w" is width. So know in order to solve this question we would have to find out the unknown width by using area and the length of the triangle. Based on the formula I wrote down earlier we can understand the following.....

A_{rectangle} = (l)(w)

\frac{A_{rectangle} }{l}  = \frac{(l)(w)}{l}

w = \frac{A_{rectangle} }{l}

Just now we found out the formula that we can use to solve for the width when we know the area and the length of the rectangle. Now in order to get the answer we just have to plug in the values we know, and we get........

w = \frac{A_{rectangle} }{l}

w = \frac{11m^{2} }{(3\frac{2}{3}m )}

w = 3m

7 0
2 years ago
Pls help I need this asap​
Valentin [98]

Answer:

75%

Step-by-step explanation:

4 0
3 years ago
Every day for 5 days Jack and Jill went walking. Each day Jack walked 4/5 of a mile and Jill walked 2/3 of a mile. At the end of
DanielleElmas [232]

\bf \stackrel{\textit{Jack for 7 days}}{7\left( \cfrac{4}{5} \right)}\implies \cfrac{28}{5}~\hspace{10em}\stackrel{\textit{Jill for 7 days}}{7\left( \cfrac{2}{3} \right)}\implies \cfrac{14}{3}
\\\\[-0.35em]
~\dotfill\\\\
\cfrac{28}{5}-\cfrac{14}{3}\implies \stackrel{\textit{LCD of 15}}{\cfrac{(3)28-(5)14}{15}}\implies \cfrac{84-70}{15}\implies \cfrac{14}{15}

7 0
2 years ago
In a recently administered iq test, the scores were distributed normally, with mean 100 and standard deviation 15. what proporti
iragen [17]

To solve for proportion we make use of the z statistic. The procedure is to solve for the value of the z score and then locate for the proportion using the standard distribution tables. The formula for z score is:

z = (X – μ) / σ

where X is the sample value, μ is the mean value and σ is the standard deviation

 

when X = 70

z1 = (70 – 100) / 15 = -2

Using the standard distribution tables, proportion is P1 = 0.0228

 

when X = 130

z2 = (130 – 100) /15 = 2

Using the standard distribution tables, proportion is P2 = 0.9772

 

Therefore the proportion between X of 70 and 130 is:

P (70<X<130) = P2 – P1

P (70<X<130) = 0.9772 - 0.0228

P (70<X<130) = 0.9544

 

Therefore 0.9544 or 95.44% of the test takers scored between 70 and 130.

6 0
3 years ago
What is the mean and median?
timama [110]

Answer:

Step-by-step explanation:

Mean roughly means the average of all the results. Add all of them up and divide it by the number of items there are. Median, basically means, you line them up from low to high numerically and the middle number.

6 0
2 years ago
Read 2 more answers
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