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4 years ago

What three things might influence a slide when conditions are right? What types of material can make up a flow?

1 answer:

5 0

The three things that can affect a condition to enforce a slide is friction, weight, and slope of an area. Solutions that can make flow easily are those that can create less friction depending on the condition of an environment where it is present. Some of these materials are water, oil, and dense liquids.

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Uranus is unique among the planets in that it

Anvisha [2.4K]

The answer is A)

Here are some informations you should know:

Uranus is the seventh planet from the sun and the third giant gas planet. It rotates like all planets. But Uranus tilts far to one side. Instead of rotating in an upright position, Uranus rolls along like a bowling ball. Uranus also travels very slowly. Uranus has 27 moons. It takes 84 Earth days to complete one orbit.

3 0

4 years ago

Read 2 more answers

A conducting strip of width 1.5 mm is in a magnetic field. As a result, there is a potential difference of 4.3 mV across the wid

OLga [1]

To solve this problem we will apply the concepts related to the Voltage depending on the Electric field and the distance where it is applied. The relationship of this relationship is given in the following form:

$V= Ed \rightarrow E = \frac{V}{d}$

Here,

E = Electric Field

V = Voltage

d = Distance

Our values are given as,

$d = 1.5mm = 1.5*10^{-3} m$

$V = 4.3 mV$

$V = 4.3*10^{-3}V$

Replacing at the first equation we have,

$E = \frac{4.3*10^{-3}}{1.5*10^{-3}}$

$E = 2.866V/m$

Therefore the electric field in the strip is 2.866V/m

6 0

3 years ago

if length of the spring is doubled, what will happen to its time period? if mass of the spring is doubled and spring constant wi

melamori03 [73]

If the length of the spring is doubled, there will be no effect on its period.

If the mass of the spring is doubled and the spring constant is halved, then its period will be doubled.

The Simple Harmonic Motion is a type of periodic motion and one of its examples is the spring-mass system.

The period of a spring mass system is given by the following equation,

T= 2π√m/√k

Here, T= period of spring

m= Mass of the body attached to the spring

k= Spring constant

According to the above equation, the period of a spring depends on the mass of the body and the spring constant.

It is independent of the length of the spring.

Therefore, if the length of spring is doubled then there will be no effect on its period.

If the mass of spring is doubled and the spring constant is halved, then the equation becomes

T'= 2π√2m/√k/2

T'= √4 x 2π√m/√k

T'= 2 x T

Hence, if the mass of the spring is doubled and the spring constant is halved, its period will be doubled.

To know more about the "spring-mass system", refer to the following link:

brainly.com/question/13156044?referrer=searchResults

#SPJ4

5 0

2 years ago

Describe what physical meaning is attributed to ψ 2

NNADVOKAT [17]

In quantum mechanics, $\psi^2$ the basic wave function has no physical meaning or significance. However, $|\psi|^2$ represents the probability distribution of particle in a given space.

Probability $\propto$ $|\psi|^2$

So when you will put a position and a time in $\psi^2$ function, it will give you the probability of finding the particle at that particular position and at the given time.

6 0

3 years ago

g Determine the magnitude of the electric field at the surface of a lead-208 nucleus, which contains 82 protons and 126 neutrons

Nookie1986 [14]

Answer:

Explanation:

Electric field at the surface of the the lead 208 = KQ/ R²

where K = 8.99 × 10⁹ Nm² /C²

Q ( total charge inside the nucleus) and e is the charge of a proton = Ne = 82 × 1.6 × 10⁻¹⁹ C = 1.312 × 10⁻¹⁷ C

V of the lead = 208 v of a proton assuming they both are sphere

4/3 πR³ =208( 4/3 πr³) where R is the radius of the sphere and r is the radius of the proton

R³ = 208 r³

R = ∛( 208 r³) = 5.92r

replace r with 1.20 x 10-15 m

R = 5.92 ×1.20 x 10-15 m = 7.11 × 10⁻¹⁵ m

E = ( 8.99 × 10⁹ Nm² /C² × 1.312 × 10⁻¹⁷ C ) / (7.11 × 10⁻¹⁵ m)² = 0.233 × 10²² N/C = 2.33 × 10²¹ N/C

4 0

3 years ago