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Fantom [35]
3 years ago
12

If a machine exerts a force of 250N on an object and no work is done, what must have occurred?

Physics
1 answer:
ss7ja [257]3 years ago
7 0
The object did not move / was kept from moving.
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Which of the following statements about the periodic table is true?
skelet666 [1.2K]

Answer:

elements are the same columns are similar in there property

Explanation:

3 0
2 years ago
How to solve these two questions? ​
hammer [34]

1) See attached figure

The relationship between charge and current is:

i = \frac{Q}{t}

where

i is the current

Q is the charge

t is the time

Therefore, the current is the rate of change of the charge passing through a given point over time.

This means that for a graph of charge over time, the current is just equal to the slope of the graph.

For the graph in this problem:

- Between t = 0 and t = 2 s, the slope is

\frac{50-0}{2-0}=25 C/s

therefore the current is

i = 25 A

- Between t = 2 s and t = 6 s, the slope is

\frac{-50-(50)}{6-2}=-25 C/s

therefore the current is

i = -25 A

- Between t = 6 s and t = 8 s, the slope is

\frac{0-(-50)}{8-6}=25 C/s

therefore the current is

i = 25 A

The figure attached show these values plotted on a graph.

2) 15 \mu C

The previous equation can be rewritten as

Q = i t

This equation is valid if the current is constant: if the current is not constant, then the total charge is simply equal to the area under a current vs time graph.

Here we have the current vs time graph, so we gave to find the area under it.

The area of the first triangle is:

A_1 = \frac{1}{2}(0.001 s)(0.010 A)=5\cdot 10^{-6} C

While the area of the second square is

A_2 = (0.002 s - 0.001 s)(0.010 A)=1\cdot 10^{-5}C

So, the total area (and the total charge) is

Q=A_1 +A_2 = 5\cdot 10^{-6} + 1\cdot 10^{-5} = 1.5\cdot 10^{-5}C=1.5 \mu C

3 0
3 years ago
Which BEST describes the speed and velocity of the graph?
Neko [114]
I think the answer is A (sorry if it isn't).
6 0
3 years ago
Read 2 more answers
• How does wind shape Earth’s surface?
ehidna [41]

Lamina and turbulent flow

Explanation:

mentioning about lamina and turbulent flow we could say that both form in different period of time

6 0
3 years ago
A transformer has a primary coil with 106 turns and a secondary coil of 340 turns. The AC voltage across the primary coil has a
UkoKoshka [18]

To solve this problem it is necessary to apply the concepts related to transformers, that is to say passive electrical device that transfers electrical energy from one electrical circuit to one or more circuits.

From the mathematical definition we have that the relationship between the voltage of the first coil and the second coil is proportional to the number of loops of the first and second loop, that is:

\frac{V_s}{V_p} = \frac{N_s}{N_p}

Where

V_p =  input voltage on the primary coil.

V_s=input voltage on the secondary coil.

N_p=  number of turns of wire on the primary coil.

N_s = number of turns of wire on the secondary  coil.

Replacing our values we have:

V_p = 128V

N_p = 106

N_s = 340

Replacing,

\frac{V_s}{128} = \frac{340}{106}

V_s = 410.56V

From the same relations of number of turns and the voltage of the first and second coil we also have the relation of electricity and voltage whereby:

V_s I_s = V_p I_p

Where

I_p= Current Primary Coil

I_s = Current secundary Coil

Therefore:

I_s = \frac{V_p I_p}{V_s}

I_s = \frac{(128)(6)}{410.56}

I_s = 1.87 A

Therefore the maximum values for the secondary coil of the voltage is 410.56V and Current is 1.87A

5 0
3 years ago
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