(1) The vertical magnitude of the ball's initial velocity is 16.075 m/s,
(2) The maximum height of the ball is 13.18 m
(1) To Calculate the vertical component of the ball's initial velocity, we use the formula below.
Formula:
- Vy = Vsin∅........................ Equation 1
Where:
- Vy = vertical component of the ball's initial velocity
- V = Initial velocity of the ball
- ∅ = angle to the horizontal.
From the question,
Given:
Substitute these values into equation 1
- Vy = 25(sin40°)
- Vy = 25×0.643
- Vy = 16.075 m/s.
(2) To calculate the maximum height reached by the ball, we use the formula below.
Formula:
- H = (Vy)²/2g............... Equation 2
Where:
- g = Acceleration due to gravity = 9.8 m/s²
Substitute the value above into equation 2
- H = (16.075)²/(2×9.8)
- H = 13.18 m
Hence, (1) The vertical magnitude of the ball's initial velocity is 16.075 m/s, (b) The maximum height of the ball is 13.18 m.
Learn more about maximum height here: brainly.com/question/13665920
Based on wind resistance?
Answer: The torque required is 0.0471 N m.
Explanation:
Mass of the disc = 200 g = 0.2 kg (1 kg =1000 g)
Radius of the disc =
= 10 cm = 0.1 m(1 m = 100 cm)
Angular acceleration = 
Moment of inertia = 
The torque required is 0.0471 N m.
Explanation:
use the diagram^
horizontal velocity of the object nvr changes, it'll stay 50m/s till it hits the ground
initial vertical velocity = 0
to find the final vertical velocity, use the formula:
where u = 0m/s, a = 9.8m/s², and s = 2000m
solve for v.
for time taken to reach ground, use the formula:
where v = the value for v u calculated above, u = 0 m/s, a = 9.8m/s² and solve for t.
