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4 years ago

Is x=5 and y=7 parallel,perpendicular or neither

Mathematics

2 answers:

Amanda [17]4 years ago

7 0

Answer:

Perpendicular

Step-by-step explanation:

when graphed they intersect

LenaWriter [7]4 years ago

3 0

Answer:

Perpendicular

Step-by-step explanation:

The lines end up crossing.

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There are 18 girls in mr.brimleys class. If 60 percent of the students are girls how many students are in mr.brimley’s math clas

emmainna [20.7K]

Answer:

30 students in the class.

Step-by-step explanation:

There are several which in which we can approach this question:

We can do this question using direct proportion.

"If 18 girls represent 60%, how many students represent 100%?"

100

students altogether.

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3 years ago

Solve for b.<br>7b - 15 = 5b - 3

guapka [62]

Answer: b=6

Step-by-step explanation: subtract 5b from both side and get 2b-15=-3 then add 15 on both side to get 2b=12 then divide 2 on both side and get b=6.

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3 years ago

Find the surface area of the triangular prism shown below.<br> units

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Step-by-step explanation:

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3 years ago

Read 2 more answers

At the zoo tje ratio of snakes to lizards is 3:2 A. If there were 10 lizards ,how many snakes would be there be? B.If there were

yawa3891 [41]

Answer:

Part A) $15\ snakes$

Part B) $6\ lizards$

Part C) The zoo would need to get four more lizards to maintain the same proportion

Part D) 12 snakes and 8 lizards

Step-by-step explanation:

Part A) If there were 10 lizards ,how many snakes would be there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

we have that

$y=10\ lizards$

substitute the value of y in the equation A

$\frac{x}{10}=\frac{3}{2}$

solve for x

$x=10(3)/2\\x=15\ snakes$

Part B) If there were 9 snakes ,how many lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

we have that

$x=9\ snakes$

substitute the value of x in the equation A

$\frac{9}{y}=\frac{3}{2}$

solve for y

$y=9(2)/3\\y=6\ lizards$

Part C) If the number of snakes in the zoo is increased by 6, how many more lizards would the zoo need to get to keep the same ratio?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

For $x=6\ snakes$

substitute the value of x in the equation A

$\frac{6}{y}=\frac{3}{2}$

solve for y

$y=6(2)/3\\y=4\ lizards$

therefore

The zoo would need to get four more lizards to maintain the same proportion

Part D) If the total number of snakes and lizards at the zoo was 20, how many snakes and lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$

isolate the variable x

$x=1.5y$ ----> equation A

$x+y=20$ ----> equation B

solve the system by substitution

substitute equation A in equation B

$1.5y+y=20$

solve for y

$2.5y=20$

$y=8\ lizards$

Find the value of x

$x=1.5(8)=12\ snakes$

therefore

12 snakes and 8 lizards

8 0

3 years ago

Inga can earn $375 per week in a plant store, or she can earn 3% of total sales. How much would Inga have to sell to earn more i

qwelly [4]

Answer:

Inga will have to sell $12,533 to earn more in commission than in salary.

Step-by-step explanation:

As the commission is the percentage of sales amount so, need to calculate the minimum sales value required.

Igna's salary = $375

Commission rate = 3%

Sale to earn more than salary = $376 / 3% = $12,533.33

Igna has to make a minimum sale of $12,533 per week in order to earn more commission than her salary.

8 0

3 years ago