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EastWind [94]
3 years ago
10

Is x=5 and y=7 parallel,perpendicular or neither

Mathematics
2 answers:
Amanda [17]3 years ago
7 0

Answer:

Perpendicular

Step-by-step explanation:

when graphed they intersect

LenaWriter [7]3 years ago
3 0

Answer:

Perpendicular

Step-by-step explanation:

The lines end up crossing.

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Is 13 a perfect cube , perfect square , or neither
denis-greek [22]

Answer:

neither

Step-by-step explanation:

if we cube root or square root thirteen, the result will be in decimal. So thirteen is neither a perfect square nor a perfect cube

Please mark as brainliest

5 0
3 years ago
Read 2 more answers
Will give brainliest
pychu [463]

Answer:

Since the only numbers that are not 0 appear in the groups 5 < d ≤ 10 to 30 < d ≤ 35 the range is 5 < d ≤ 35.

8 0
3 years ago
Please help me (0^0)/&lt;3
harkovskaia [24]

Answer:

C or A

Step-by-step explanation:

4 0
3 years ago
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Can you help me to solve this
stealth61 [152]

Answer:

\text{Triangle 1:}\\\\x=30\sqrt{2},\\\\\text{Triangle 2:}\\x\approx 36.18,\\?\approx12.37

Step-by-step explanation:

*Notes (clarified by the person who asked this question):

-The triangle on the right has a right angle (angle that appears to be a right angle is a right angle)

-The bottom side of the right triangle is marked with a question mark (?)

<u>Triangle 1 (triangle on left):</u>

Special triangles:

In all 45-45-90 triangles, the ratio of the sides is x:x:x\sqrt{2}, where x\sqrt{2} is the hypotenuse of the triangle. Since one of the legs is marked as 30, the hypotenuse must be \boxed{30\sqrt{2}}

It's also possible to use a variety of trigonometry to solve this problem. Basic trig for right triangles is applicable and may be the simplest:

\cos 45^{\circ}=\frac{30}{x},\\x=\frac{30}{\cos 45^{\circ}}=\frac{30}{\frac{\sqrt{2}}{2}}=30\cdot \frac{2}{\sqrt{2}}=\frac{60}{\sqrt{2}}=\frac{60\cdot\sqrt{2}}{\sqrt{2}\cdot \sqrt{2}}=\frac{60\sqrt{2}}{2}=\boxed{30\sqrt{2}}\\

<u>Triangle 2 (triangle on right):</u>

We can use basic trig for right triangles to set up the following equations:

\cos 20^{\circ}=\frac{34}{x},\\x=\frac{34}{\cos 20^{\circ}}\approx \boxed{36.18},

\tan 20^{\circ}=\frac{?}{34},\\?=34\tan 20^{\circ}\approx \boxed{12.37}

We can verify these answers using the Pythagorean theorem. The Pythagorean theorem states that in all right triangles, the following must be true:

a^2+b^2=c^2, where c is the hypotenuse of the triangle and a and b are two legs of the triangle.

Verify 34^2+(34\tan20^{\circ})^2=\left(\frac{34}{\cos20^{\circ}}\right)^2\:\checkmark

3 0
3 years ago
Fill in the numbers I’m so stuck on what to fill in these empty boxes
galben [10]

Answer:

96, 97

64,65

57, 66

71, 72

26,36

second row

13

34

57

65

52

Step-by-step explanation:

Fill in the numbers: It's the 100s chart cut into pieces. You are looking for numbers that are 1 less, 1 more, 10 less or 10 more than a number.

5 0
3 years ago
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