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3 years ago

Factor the following Polynomial both 13 and 14

Mathematics

1 answer:

Maksim231197 [3]3 years ago

8 0

A•B=C
A•B=-21
Find factors of 21 ( it doesn't matter that it's negative ) that at up to be 4
It's 7and 3
Then put x^2+7x+3x-21 and then factor by grouping
Do the same steps for #2

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Please solve in the next 10 minutes pleaseeee

Alex787 [66]

Answer:

43.82 mph

266.67 feet

Step-by-step explanation:

Given :

S = √30fl

S = speed of car

f = drag Coefficient

l = Length of skid mark

If f = 0.8 ; l = 80 feets

s = √30fl

s = √(30*0.8*80)

s = √1920

s = 43.817

s = 43.82 mph

B.)

s = 80 mph

f = 0.8

s = √30fl

80 = √30*0.8*l

80 = √24l

Square both sides

80² = 24l

6400 = 24l

l = 6400/24

l = 266.67 feets

6 0

3 years ago

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Veronika [31]

Answer:

I think its c

Step-by-step explanation:

3 0

3 years ago

Please help with this question

leonid [27]

We know that $\sin(45)=\cos(45)$ and this is the only point when sin and cos are equal lengths. Because both $\sin(45),\cos(45)=\dfrac{\sqrt{2}}{2}$

Now if the sin of 30° is a half that would mean that cos of 60° is also a half.

Hope this helps.

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4 years ago

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pantera1 [17]

<h3>Answer: Choice D) </h3>

Work Shown:

$(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\$

We must require that $x \ne -12$ and $x \ne 3$ to avoid having 0 in the denominator. This is why choice D is the answer.

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Complete the scale by labeling the remaining tick marks

scoundrel [369]

Answer:

Can you provide a picture?

I cannot help you if you don't.

5 0

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