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antoniya [11.8K]
3 years ago
10

The lengths of the sides of a triagle are 12, 13, and n. Which of the following must be true.

Mathematics
1 answer:
vampirchik [111]3 years ago
4 0
By the triangle inequality theorem we know that
b - a < c < a+b
where a and b are the given sides; c is the unknown side

In this case,
a = 12
b = 13
c = n

So,
b-a < n < b+a
13-12 < n < 13+12
1 < n < 25

So n is both greater than 1 and also less than 25
Broken up, this means n > 1 and n < 25

So it looks like the only answer is choice A. Choices C and D seem to have typos in them? Something seems off about them. 
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How can u convert a fraction to a decimal if the fraction has a multiple of 10 in the denominator
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5 1/8*1 1/3 what is the answer
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3 years ago
Read 2 more answers
segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc
Elan Coil [88]

Answer:

The magnetic field is B = 3.87 *10^{-6} \ T

Direction is inward

 

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image  

From the question we are told that

      The radius of  BC is  r_{BC} =  30 \ cm  =  0.30 \ m

      The radius of  DA is r _{DA} =  20 \ cm =  0.20 \ m

      The length of CD is  r_{CD} =  10 cm =  0.1 \ m

      The length of AB is  r_{AB} =  10 cm =  0.1 \ m

      The current is  I  =  11.4A

The magnetic field is mathematically represented as

      B =  B_{BC} +  B_{DA} + B_{CD} + B_{AB}

       B =  \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]

        Where

                 \theta_{BC} = \theta_{DA} =  \frac{2\pi}{3}

Where  \frac{2 \pi}{3}  =  120^o

                \theta_{CD} = \theta_{AB}  =  0^o

so

        B =  \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]

         B = 3.87 *10^{-6} \ T

The direction is into the page

    This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule  the direction of current is perpendicular to the direction of magnetic field so since  current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

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3 years ago
Express in simplest radical form.<br> \frac{\sqrt{96}}{2}
Gelneren [198K]

Answer:

\frac{ \sqrt{96} }{2}  =  \frac{ \sqrt{16 \times 6} }{2}  =  \frac{4\sqrt{6} }{2}  = \boxed{2 \sqrt{6}}\\

<h3><em><u>2√6</u></em> is the right answer.</h3>
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