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antoniya [11.8K]

3 years ago

10

The lengths of the sides of a triagle are 12, 13, and n. Which of the following must be true.

1 answer:

vampirchik [111]3 years ago

4 0

By the triangle inequality theorem we know that
b - a < c < a+b
where a and b are the given sides; c is the unknown side

In this case,
a = 12
b = 13
c = n

So,
b-a < n < b+a
13-12 < n < 13+12
1 < n < 25

So n is both greater than 1 and also less than 25
Broken up, this means n > 1 and n < 25

So it looks like the only answer is choice A. Choices C and D seem to have typos in them? Something seems off about them.

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The sum of two numbers is 98. their difference is 22. write a system of equations that describes this situation. solve by elimin

larisa [96]

Y+x=98
y-x=22

I'm going to use elimination.

y+x=98
y-x=22
-----------
2y+0x=120 SIMPLIFY 2y=120 SIMPLIFY y=60.

Substitute that into either equation and you get y=60 and x=38

Have a nice day! :)

6 0

3 years ago

How do I solve this out??

GuDViN [60]

<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

$\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]$

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

$\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]$

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0

3 years ago

What of the following functions is graphed below

leva [86]

The correct answer is C

5 0

3 years ago

Find the distance between the points (6,5√5) and (4,3√2).<br> 2, 2√2, 2√3

FromTheMoon [43]

Answer:

D= $\sqrt{(147-30\sqrt{10}}$

Step-by-step explanation:

Here we are required to find the distance between two coordinates. We will use the distance formula to find the distance

The distance formula is given as

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Here we are given two coordinates as

$(6,5\sqrt{5} ) , (4,3\sqrt{2} )$

Substituting these values in the Distance formula given above we get

$D=\sqrt{(6-4)^2+(5\sqrt{5} -3\sqrt{2}) ^2}$

$D=\sqrt{(2)^2+(5\sqrt{5})^2+(3\sqrt{2})^2-2*5\sqrt{5}*3\sqrt{2}}\\$

$D=\sqrt{4+125+18-2*15\sqrt{10}}\\D=\sqrt{147-30\sqrt{10}}\\$

Hence this is our answer

6 0

3 years ago

Solve the following system of equations algebraically.<br> x + 2y = 18<br> y = x-3<br> X=<br> y =

ivolga24 [154]

Answer:

x + 2y - 18 =0

y = x - 3 is x = 3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers