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attashe74 [19]
3 years ago
6

Which rectangle is similar to a rectangle 12 inches wide and 18 inches long

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

I think we need pictures

Step-by-step explanation:

do you have any pictures we could use to try and help

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HELP ASAP 50 POINTS
serg [7]
<h3>Part A</h3>

<u>Factoring the area:</u>

  • 4x² + 20x + 25 =
  • (2x)² + 2*2x*5 + 5² =
  • (2x + 5)²

<u>The length of the side is:</u>

  • √(2x + 5)² =
  • 2x + 5
<h3>Part 2</h3>

<u>Factoring the area:</u>

  • 4x² − 9y²=
  • (2x)² - (3y)² =
  • (2x + 3y)(2x - 3y)

<u>The sides of the rectangle are:</u>

  • 2x + 3y and 2x - 3y
7 0
3 years ago
M = y2 - y1 / x2 - x1 What is the slope of line JK? A) 5/9 B) 9/5 C) -5/9 D) -9/5
meriva
So
(x,y)

J is -4 to the right and 2 up so
(-4,2)

K is 5 to the right and -3 up
(5,-3)

(x,y)

x1=-4
y1=2
x2=5
y2=-3

M=\frac{y2-y1}{x2-x1}
M=\frac{-3-2}{5-(-4)
M=\frac{-5}{5+4}
M=\frac{-5}{9}


answer is C -5/9
3 0
4 years ago
Read 2 more answers
What value of x will make AONM similar to ASRQ by
Rashid [163]

Answer:

16 for sure ...

Step-by-step explanation:

16 for sure . which grade question is this ?

8 0
3 years ago
The length of a rectangle is
melomori [17]

Answer:

L= 11 m and W = 2 m

Step-by-step explanation:

Let's convert the sentences into mathematical expressions, for which we need to assign letters to the unknowns: length and width of a rectangle.

Let's identify the rectangle's length with the letter "L', and its width with the letter "W".

Then we can write:

"The length of a rectangle is  3  meters more than  4  times the width."

as: L = 4 * W + 3

The second sentence says:

"The area (of the rectangle) is 22 square meters", so to write this in mathematical terms we need to recall the formula for the area of a rectangle:

Area = Length * Width   (the product of the rectangle's length times its width)

Therefore the second sentence can be converted into the following equation:

Area = L * W = 22

Now we can use the first mathematical expression we constructed in the second formula so we can reduce the number of unknowns  from two (L and W) to only one (W) and solve for it in the equation.

We replace "L" with 4 * W + 3 (from our first expression) in the area formula:

L * W = (4 * W + 3) * W = 22

4W^2 + 3W = 22\\4W^2+3W-22=0

Which is a quadratic equation in W, and which has solutions given by the quadratic formula:

ax^2+bx+c=0\\

x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

For our unknown W (instead of "x") and our parameters:

a=4, b=3, c=-22

the quadratic formula would be:

W=\frac{-3+/- \sqrt{3^2-4(4)(-22)} }{2(4)}=\frac{-3+/- \sqrt{9+352} }{8}= \frac{-3+/- \sqrt{361} }{8}=\frac{-3+/-19 }{8}This gives as two possible solutions (one using the plus and the other using the minus):

W=\frac{-3-19}{8} =\frac{-22}{8}=-\frac{11}{4} \\W=\frac{-3+19}{8} =\frac{16}{8}=2 \\

the negative answer has no physical meaning in our case because we are dealing with positive dimensions for a rectangle. Therefore the only logical solution for W is: 2 meters

Now we use the first expression we found for "L" to find its value:

L = 4 (2) +3 = 8 + 3 = 11 meters

7 0
4 years ago
Geometry. What is the value of x?
Yuliya22 [10]
Given that the length's of the secant's are equal, it implies that the distance of a perpendicular bisector from the secant to the center of the circle will also be the same. This implies that the value of x will be given by:
x=16
8 0
4 years ago
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