What of the following functions is graphed below

I need the answer now please

xxMikexx [17]

Answer:

180/147

Step-by-step explanation:

We need to find the additive inverse of the given numbers.

For finding it we may simply out -1 as multiplication in front of the terms .

SOLUTION 1 :-

→ 3/-7 - 11/21

→ -3/7 -11/21

→ 3×-3 - 11 /21

→ -9-11/21

→ -20/21

SOLUTION 2 :-

→ 9/5 ÷ 7/5

→ 9/5 × 5/7

→ 9/7

→ Product of nos . = -20/21 × -9/7

→ Ans = 180/147

7 0

3 years ago

What is 80/6 as a simplified fraction

Nat2105 [25]

Here is the answer for math problem

7 0

3 years ago

Read 2 more answers

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

2 years ago

You are in charge of planning a reunion party for your high school alumni. The food will cost $12 per person. The rental fee for

castortr0y [4]

Answer:

$3820 total, $32 per alumnus.

Step-by-step explanation:

The total cost will be $12\times120+650+730+1000=3820$