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slega [8]
4 years ago
9

Sebastian and Amy both ride from their homes to the park from the Park to Amy’s home it is 3 miles from the Park to Sebastian’s

home is 3 miles as well if they both start at the same time in ride at their current rate how long will one have to wait for the other to arrive
Mathematics
1 answer:
TiliK225 [7]4 years ago
6 0
They shouldn’t have to wait for each other because they are doing everything the same.
Both 3 miles away, both start at the same time, both at current rate
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Please help me i’m stuck
Studentka2010 [4]
Following the principle of supplements angles, the angle next to the 101 is 79°. 79+38+c(call the third angle c) = 180
c = 180-117 =63° x is supplemental to c so 180 = x +c
180=x + 63
x =117
5 0
1 year ago
In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate
oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = \pi×14 = 44 cm

length of arc ab = half of circumference of bigger circle  = \pi×28 =\frac{22}{7}×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

                                           =\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}

                                           =\frac{\pi }{2} (28^{2} -14^{2} )

  solving we gen area of shaded region = 924

7 0
3 years ago
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PolarNik [594]
Question 2: peaceful protests without violence

3 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
Use the GCF and the Distributive Property to express the sum as a product. 30 + 10
Inessa [10]

The expression that uses the GCF and the Distributive Property to express the sum as a product of the expression given as 30 + 10 is 10(3 + 1)

<h3>How to use the GCF and the Distributive Property to express the sum as a product?</h3>

The expression is given as:

30 + 10

Express the terms of the expression as the product of their GCF.

So, we have:

30 + 10 = 3 * 10 + 1 * 10

Factor out 10

30 + 10 = 10(3 + 1)

Hence, the expression that uses the GCF and the Distributive Property to express the sum as a product of the expression given as 30 + 10 is 10(3 + 1)

Read more about Distributive Property at

brainly.com/question/4077386

#SPJ1

6 0
1 year ago
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