Find the length of the hypotenuse. O A. 17/2 O B. 5/7 O C. 3/2 OD. 7/3

Which algebraic expression shows the average melting points of helium, hydrogen, and neon if h represents the melting point of h

LenKa [72]

Average = mean = sum of the values / number of data

Values = h, j, and k

Number of data = 3

Sum of the values = h + j + k

Mean = [h + j + k] / 3

=> Answer: option c. [h+j+k] over 3

4 0

3 years ago

Read 2 more answers

if my grade is 69% what will my grade be if i got a 3.3 of 4 on a essay and it's worth 25% of my grade?

juin [17]

Answer:

72.4%

Step-by-step explanation:

The essay is 25% of your grade, and the rest is 75% of your grade.

25 (3.3/4) + 75 (0.69) ≈ 72.4

6 0

3 years ago

What percentage of 5/2 hours is 15 minutes?

elena-14-01-66 [18.8K]

Answer:

10 %

Step-by-step explanation:

15 mn = 1/4 h

We have :

$\frac{\frac{1}{4} }{\frac{5}{2} } =\frac{1}{4} \times \frac{2}{5} =\frac{2}{20} =\frac{1}{10}=0.1$

Then the percentage that 15 mn represents of 5/2 h is :

0.1 × 100 = 10 %

5 0

2 years ago

Nth term of -7, -12, -17, -22

frosja888 [35]

Answer:

-27,-32,-37,-42,-47

Step-by-step explanation:

5 0

3 years ago

In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour

Lesechka [4]

Answer:

$54-1.64\frac{21}{\sqrt{16}}=45.39$

$54 +1.64\frac{21}{\sqrt{16}}=62.61$

So on this case the 90% confidence interval would be given by (45.39;62.61)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=54$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=21$ represent the sample standard deviation

n=16 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$

Now we have everything in order to replace into formula (1):

$54-1.64\frac{21}{\sqrt{16}}=45.39$

$54 +1.64\frac{21}{\sqrt{16}}=62.61$

So on this case the 90% confidence interval would be given by (45.39;62.61)

4 0

4 years ago