They would have about 8 pounds of dry cat food…to be specific, 8 remainder 2
Answer:
Step-by-step explanation:
A = P[1 + (r/n)]^(nt)
Look the formula up online to find out what each variable represents if needed.
We are solving for P, which is the principal amount 5 years back.
Substitute 11,000 for A (total amount), 4.5% for r(rate), 2 for n(number of times -- in this case, semiannually), and 5 for t(time -- 5 years).
11000 = P[1+(0.045/2)]^(2x5)
11000 = P (1.0225)^10
11000 = P (1.2492) approx.
Divide both sides by 1.2492 to find P.
P = $8805.64 (approx)
I know that the answer I got is not an option listed. However, I feel that my workings may help other people to answer this question or give them inspiration to answer similar questions. Therefore, I will leave this answer up.
Thanks, and sorry I couldn't do much.
Answer:
The initial cash balance in bank is $46
Step-by-step explanation:
The equation given to determine b which is the initial money before she withdrew $60 is
b + (-60) = -14
Let's solve for the value of b which is the initial balance of the money in the bank.
b + (-60) = -14
b -60 = -14
b = -14+60
b = 60-14
b = 46
The initial money before she withdrew $60 was $46
Answer:
$1.75
Step-by-step explanation:
The selling for each candy bar may be determined by a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.
It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation
.
Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25
23s + 36c = 114.75
37s + 36c = 146.25
14s = 31.5
s = $2.25
23(2.25) + 36c = 114.75
36c = 114.75 - 51.75
36c = 63
c = 63/36
= $1.75
