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3 years ago

Solve the proportion 15t/5=(2t+3)/6.

Mathematics

1 answer:

sp2606 [1]3 years ago

5 0

$\frac{15t}{5} = \frac{2t + 3}{6} \\ 90t = 10t + 15 \\ 80t = 15 \\ t = 0.1875$

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Is the sum of two rational numbers always rational

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Answer:

in short, Yes they are always rational.

here's why...

E.g. suppose $\frac{c}{d}$ and $\frac{a}{b}$ are fractions, that means that a,b,c,d are all integers, and b and d are not zero. finding the sum the numerator, and denominator would also have to be integers. the denominator of the sum can't be zero since the denominators of the fractions were not zero, and would give $\frac{ad+bc}{bd}$ and since they are bound by addition (sum means addition) they must also be rational since eit would equal a bigger integer than initially had

Step-by-step explanation:

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2 years ago

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3 years ago

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Brainliest please-

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3 years ago

M + 6 = 3m + 14<br> Solve?

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Answer:

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25 POINTS AND BRAINLIEST PLEASE HELP ASAP

dexar [7]

M is a midpoint of BC so:

$M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)$

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$MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
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Length of NB:

$NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
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3 years ago

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