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elena55 [62]
3 years ago
10

What degree is an obtuse angle​

Mathematics
2 answers:
NemiM [27]3 years ago
5 0
It’s greater than 90 degrees but less than 180 degrees
lilavasa [31]3 years ago
4 0
A really big one that is larger that the acute angel
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What is the solution to (5m)² - (2n-3m)³ if m=-3 and n=5
Nimfa-mama [501]

Answer:

-6634

Step-by-step explanation:

(5m)² - (2n-3m)³ if m=-3 and n=5

= (5 * (-3))^2 - (2 * 5 - 3 * (-3))^3

= (-15)^2 - (10 - (-9))^3

= 225 - (19)^3

= 225 - 6859

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3 years ago
The angles of a triangle are 2x, 3x, and 4x degrees. Find the value of x.
dimulka [17.4K]
<span>We have to find the value of x if the measures of the angles of a triangle are: 2 x, 3 x and 4 x. We know that the sum of the measures of the angles of a triangle is 180 degrees. A + B + C = 180. Here we have: A = 2 x, B = 3 x and C = 4 x; 2 x + 3 x + 4 x = 180; 9 x = 180; x = 180 : 9. Answer: x = 20 degrees.</span>
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3 years ago
The polynomial x2 + 7x – 44 can be factored.
Virty [35]

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Step-by-step explanation:

(x-4)(x+11)

x^2-4x+11x-44

x^2+7x-44

Ding Dong!

5 0
3 years ago
Problem 5. A skating rink in the shape shown has an area of
nexus9112 [7]

Answer:

P=\dfrac{\pi r^2+2800}{r} $ ft

Step-by-step explanation:

Let the length of the rectangular part =l

The width will be equal to the diameter of the semicircles.

Area of the Skating Rink= 2(\frac{\pi r^2}{2})+(lX2r)

Therefore:

\pi r^2+2lr=2800\\2lr=2800-\pi r^2\\$Divide both sides by 2r\\l=\dfrac{2800-\pi r^2}{2r}

Perimeter of the Shape =Perimeter of two Semicircles + 2l

=2\pi r+2\left(\dfrac{2800-\pi r^2}{2r}\right)\\=2\pi r+\dfrac{2800-\pi r^2}{r}\\=\dfrac{2\pi r^2+2800-\pi r^2}{r}\\=\dfrac{\pi r^2+2800}{r}

The perimeter of the rink is given as:

P=\dfrac{\pi r^2+2800}{r} $ ft

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3 years ago
What is the profit the performer makes at a performance where 8 people attend?
otez555 [7]
120 : 8 = 15
and 15 x 20 = 300, so the answer is C
4 0
4 years ago
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