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AfilCa [17]
3 years ago
9

The two shorter sides of a triangle are the same length. The length of the longer side is 5 m longer than each of the shorter si

des. The perimeter of the triangle is 29 m.
What is the length of the longest side of the triangle?

8 m

12 m

13 m

17 m
Mathematics
1 answer:
Korolek [52]3 years ago
3 0
13 m.
29 - 5 = 24
24/3=8
8+5=13
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ethan took a quiz with 15 questions. if he answered 3/5 of the questions correctly, how many did he get wrong?
valentina_108 [34]
\frac{15}{1} *  \frac{3}{5} =  \frac{45}{5} = 9 
 





15-9= 6
Ethan got six questions wrong. 
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If a triangle has one obtuse angle, then it is an obtuse triangle.
nalin [4]
No the sum of measures would exceed 180, therefore it would not be a obtuse triangle
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A bicycle manufacturing plant is producing the first few frames for their new electric bicycle design. The first batch of 60 fra
Dmitry_Shevchenko [17]

Answer:

a) 131/450

b) 1233/1276  

Step-by-step explanation:

P(bad) = P(1st batch)*P(bad 1st batch ) + P(2nd batch )*P(bad 2nd batch) + P(3rd batch )*P(bad 3rd batch)

p(bad) =(60/360)*(1/3) + (120/360)*(1/4 ) + (180/360)*(1/5)

= 43/180  

And that of  P(good )

= 1 - 43/180

= 137/180

a)

P(defective) = P(bad)*P(defective /bad) + P(good)*P(defective /good)

= (43/180)*(9/10) + (137/180)*(1/10)

= 131/450

b)

P(Bc I Dc ) = P(good)*P(not defective |good) / P(not defective)

= (137/180)*(1 - 1/10) / (1 - 131/450)

= 1233/1276  

5 0
3 years ago
Please urgent answer needed
Daniel [21]

Answer:

8

Step-by-step explanation:

5 0
3 years ago
find the equation of the sides of an isosceles right angled triangle whose vertex is (-2,-3) and the base is on the line x=0​
Serggg [28]

Answer:

AC:y=x-1  CB:y=-x-5 AB:x=0

Step-by-step explanation:

Consider the triangle. The base AB is on the line x=0, the vertex C is (-2,-3)

The side AC is equal to BC. The angle ACB is 90 degrees. If the base is on the line x=o, it is on the axis Y.Explore the distance from the point C to the AB

c(-2,-3), the distance to the axis Y is equal to the modul of the coordinate x (-2), it is 2. The coordinates of point projected by the point C to the axis Y is N(0,-3). The modul of the height is 2, the height of the isosceles triangle to the base is the bisectrix, so the angle BCA is 90/2=45degrees, CBA is 180-90-45=45 degrees too

the heigt CN is equal to side NB, NB=2

Suppose B is (0,y) (x=0 because the base is on this line)

THe modul of the vector NB is equal to sqrt ((0-0)^2+(y+3)^2)= 2

modul (y+3)= 2

y=-1 or y=-5

(0,-1), (0,-5) - two points, one of them (suppose B) is (0,-5) when A is (0,-1) (A is remote from the point N on the same distance with B, because AB is the median too)

Find CB and AC

Use the equation for AC

(x-0)/(-2-0)= (y+1)/(-3+1)

x/-2= (y+1)/-2

x=y+1

y=x-1

For CB

(x-0)/ (-2-0)= (y+5)/ (-3-(-5))

x/-2= (y+5)/2

-x=y+5

y=-x-5

7 0
2 years ago
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