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Stels [109]
3 years ago
5

Four-thirds times the sum of a number and 8 is 24. what is the number?

Mathematics
1 answer:
labwork [276]3 years ago
8 0
So first you take the words and put them into an equation. "a number" that never gets directly told to you will always be a variable, which is easiest to make X. "The sum of a number and 8" will mean that 8+something is the sum so they have to go in parenthesis... giving you
 4/3*(x+8)=24
now just solve for X, remembering to use the reverse of PEMDAS, since you're solving for the variable.
remove what is furthest away to the X first.
x+8=24*3/4
x+8=18
x=18-8
x=10
Now, remember to always go through and replace your variable with its value and solve. if it is not equal on both sides, retry the problem because you may have missed a small +, -, or * somewhere!


Hope this helped:)
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Answer:

Step-by-step explanation:

First, you gotta work out the hypotenuse of ABC, which is AC.

To do that, you need to figure out the scale factor between the two right-angled triangles. You can do that for this question because this is a similar shapes question.

12.5/5 = 2.5

The scale factor length between the two triangles is 2.5.

You can use 2.5 now to work out AC, so AC would be 13 x 2.5, which gives 32.5.

Now that you've got the hypotenuse and BC of ABC, you can use Pythagoras's theorem to work out the length of AB

Pythagoras's theorem = a^2 + b^2 = c^2

a = BC = 12.5

b = AB = we need to work this out

c = AC (the hypotenuse we just worked out) = 32.5

12.5^2 + b^2 = 32.5^2 Let's both simplify and rearrange this at the same time so that we have our b on one side.

b^{2} = 1056.25 - 156.25

b = \sqrt{(1056.25 - 156.25)}

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Perimeter of ABC = AB + BC + AC

= 30 + 12.5 + 32.5

= 75  Here's the perimeter for ABC.

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