Answer:

Step-by-step explanation:
Given : The number of marbles of different colors stored in a hat is listed below:
8 red marbles
10 green marbles
6 blue marbles
To Find: What is the probability that Tessa takes out a blue marble in both draws?
Solution:
8 red marbles
10 green marbles
6 blue marbles
Total Marbles = 8+10+6= 24
Probability of getting blue marble on first draw = 
Probability of getting blue marble on first draw = 
Now the marble is replaced
Probability of getting blue marble on second draw = 
Probability of getting blue marble on second draw = 
So, probability of getting blue marble on both the draws = 
= 
= 
Hence the probability that Tessa takes out a blue marble in both draws is 