4.68 tons since you would multiply 2.1+0.5=2.6×1.8=4.68 tons
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
The advantage of the graphing calculator is that you just have to find two independent equations, introduce them in the calculator and it will find the intersection point ot the two graphs.
The equations that you have to introduce are:
1) y = 2.25x + 24
2) y = 2.75x + 23
The algebraic solution, which will give you the same coordinates of the intersection point of the graphs is
2.25x + 24 = 2.75x + 23
2.75x - 2.25x = 24 - 23
0.5x = 1 => x 1 /0.5 = 2.
Answer: 2
Answer:
2.8
Step-by-step explanation:
