Answer:
Guessing the answer should be the blue one because it is going up the graph steeper.
Step-by-step explanation:
The first one is true
<span>4(4a+10) is
</span>16 a + 40 after distribution
The second one is also true
<span>2(8a+20)
16a + 40 after distribution
Third is not true
</span><span>4a(4+10a)
</span><span>16a + 40a^2 after distribution
Last one is also true
</span><span>8(2a+5)
16a + 40 after distribution
Hope this helps :)</span>
Answer:
d its d :)
Step-by-step explanation:
i already did that
First, let's multiply the first equation by two. This is because we have to eliminate either x or y by subtraction or addition so that means either both of the x's or both of the y's in the two equations have to be equal. Thus multiplying the first equation by 2 will give 12x+8y=4.
Next, subtract equation two from equation one:
We get a third equation, 2x-0= -28
Thus, x=-28/2. x= -14
In the same way, to find y, we need to eliminate the x's in both equations. This can be done by multiplying the first equation by 5 and the second by 3
Thus : 30x+20y=10 and 30x-24y=96
Subtracting the second equation from the first, we have 0+44y=-86
y=-86/44
y = 1.96 or 43/22
For this case we have the following system of equations:
We multiply the first equation by -5:
Thus, we have the equivalent system:
We add the equations:
We find the value of the variable "x":
Thus, the solution of the system is:
Answer:
