Answer:
![\displaystyle -2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Average Rate of Change:
![\displaystyle \frac{f(b) - f(a)}{b - a}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bf%28b%29%20-%20f%28a%29%7D%7Bb%20-%20a%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
Interval -1 ≤ x ≤ 3
a = -1, b = 3
f(a) = f(-1) = 4
f(b) = f(3) = -4
<u>Step 2: Find Average</u>
- Substitute in variables [ARC]:
![\displaystyle \frac{f(3) - f(-1)}{3 + 1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bf%283%29%20-%20f%28-1%29%7D%7B3%20%2B%201%7D)
- Substitute:
![\displaystyle \frac{-4 - 4}{3 + 1}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B-4%20-%204%7D%7B3%20%2B%201%7D)
- [Fraction] Subtract/Add:
![\displaystyle \frac{-8}{4}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B-8%7D%7B4%7D)
- [Fraction] Divide:
![\displaystyle -2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-2)
Answer:
-3, 1, 4 are the x-intercepts
Step-by-step explanation:
The remainder theorem tells you that dividing a polynomial f(x) by (x-a) will result in a remainder that is the value of f(a). That remainder will be zero when (x-a) is a factor of f(x).
In terms of finding x-intercepts, this means we can reduce the degree of the polynomial by factoring out the factor (x-a) we found when we find a value of "a" that makes f(a) = 0.
__
For the given polynomial, we notice that the sum of the coefficients is zero:
1 -2 -11 +12 = 0
This means that x=1 is a zero of the polynomial, and we have found the first x-intercept point we can plot on the given number line.
Using synthetic division to find the quotient (and remainder) from division by (x-1), we see that ...
f(x) = (x -1)(x² -x -12)
We know a couple of factors of 12 that differ by 1 are 3 and 4, so we suspect the quadratic factor above can be factored to give ...
f(x) = (x -1)(x -4)(x +3)
Synthetic division confirms that the remainder from division by (x -4) is zero, so x=4 is another x-intercept. The result of the synthetic division confirms that x=-3 is the remaining x-intercept.
The x-intercepts of f(x) are -3, 1, 4. These are the points you want to plot on your number line.
Answer: ![2x^2+3x-2](https://tex.z-dn.net/?f=2x%5E2%2B3x-2)
Step-by-step explanation:
You can do long division, which is very very hard to show with typing on a keyboard. You essentially want to divide the leading coefficient for each term. Ill try my best to explain it.
Do
. Write 2x^2 down. Now multiply (x - 3) by it. Then subtract it from the trinomial.
![2x^2*(x-3)=2x^3 -6x^2\\(2x^3 -3x^2-11x+6)-(2x^3-6x^2) = 3x^2-11x+6](https://tex.z-dn.net/?f=2x%5E2%2A%28x-3%29%3D2x%5E3%20-6x%5E2%5C%5C%282x%5E3%20-3x%5E2-11x%2B6%29-%282x%5E3-6x%5E2%29%20%3D%203x%5E2-11x%2B6)
Now do
. Write that down next to your 2x^2. Multiply 3x by (x - 3) to get:
![3x(x-3)=3x^2-9x\\(3x^2-11x+6)-(3x^2-9x)=-2x+6](https://tex.z-dn.net/?f=3x%28x-3%29%3D3x%5E2-9x%5C%5C%283x%5E2-11x%2B6%29-%283x%5E2-9x%29%3D-2x%2B6)
Your final step is to do
. Write this -2 next to your other two parts
Multiply -2 by (x - 3) to get:
![-2(x-3)=-2x+6\\(-2x+6)-(-2x+6)=0](https://tex.z-dn.net/?f=-2%28x-3%29%3D-2x%2B6%5C%5C%28-2x%2B6%29-%28-2x%2B6%29%3D0)
Our remainder is 0 so that means (x - 3) goes into that trinomial exactly:
times
Answer:
![Area =55.4ft^2](https://tex.z-dn.net/?f=Area%20%3D55.4ft%5E2)
Step-by-step explanation:
Given
The attached rhombus
Required
The area
First, calculate the length of half the vertical diagonal (x).
Length x is represented as the adjacent to 60 degrees
So, we have:
![\tan(60) = \frac{4\sqrt 3}{x}](https://tex.z-dn.net/?f=%5Ctan%2860%29%20%3D%20%5Cfrac%7B4%5Csqrt%203%7D%7Bx%7D)
Solve for x
![x = \frac{4\sqrt 3}{\tan(60)}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B4%5Csqrt%203%7D%7B%5Ctan%2860%29%7D)
![\tan(60) = \sqrt 3](https://tex.z-dn.net/?f=%5Ctan%2860%29%20%3D%20%5Csqrt%203)
So:
![x = \frac{4\sqrt 3}{\sqrt 3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B4%5Csqrt%203%7D%7B%5Csqrt%203%7D)
![x = 4](https://tex.z-dn.net/?f=x%20%3D%204)
At this point, we have established that the rhombus is made up 4 triangles of the following dimensions
![Base = 4\sqrt 3](https://tex.z-dn.net/?f=Base%20%3D%204%5Csqrt%203)
![Height = 4](https://tex.z-dn.net/?f=Height%20%3D%204)
So, the area of the rhombus is 4 times the area of 1 triangle
![Area = 4 * \frac{1}{2} * Base * Height](https://tex.z-dn.net/?f=Area%20%3D%204%20%2A%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20Base%20%2A%20Height)
![Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4](https://tex.z-dn.net/?f=Area%20%3D%204%20%2A%20%5Cfrac%7B1%7D%7B2%7D%20%2A%204%5Csqrt%203%20%2A%204)
![Area =2 * 4\sqrt 3 * 4](https://tex.z-dn.net/?f=Area%20%3D2%20%2A%204%5Csqrt%203%20%2A%204)
![Area =55.4ft^2](https://tex.z-dn.net/?f=Area%20%3D55.4ft%5E2)
Answer:
602
Step-by-step explanation: