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VikaD [51]
3 years ago
14

Match with correct description

Mathematics
1 answer:
fgiga [73]3 years ago
8 0
First one:  If the leading coeff. is negative, the graph begins in Quadrant III and ends in Quadrant IV.  It's an even function.   The fourth graph represents it.

If the leading coeff. is positive, but everything else remains the same, the graph opens upward, beginning in Q II and ending in Q I.

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How many tens are there in 90,000?
Leno4ka [110]
9000 tens are in 90,000

Because:
90,000÷10=9000

If it is too much work, just cross of one zero from 90,000 which becomes:
9000

Hope this helps!
3 0
3 years ago
Determine the singular points of the following differential equation and classify each singular point as regular or irregular.
anygoal [31]
Let be
p(x)=<span>(x^{2} -1
q(x)=</span><span>3(x+1)
r(x)=1
the three coefficients of the equation
a is a singular point of the equation if   lim p(x) =0
                                                              x------>a 
so let's find a
</span> lim p(x) = lim x²-1=a²-1=0
  x------>a    x------>a 
a²-1=0 implies  a=+ or -1

so the sigular points are a= -1 or a=1

case 1
for a= -1
lim (x-(-1)) q(x)/p(x)=lim (x+1) 3(x+1)/x²-1=lim3(x+1)/x-1= 0/-2=0
x------> -1                  x------> -1                    x------> -1
lim (x-(-1))²  r(x)/p(x)= lim(x+1)²/x²-1= 0/-2=0
x------> -1                    x------> -1

lim (x-(-1)) q(x)/p(x) and lim (x-(-1))²  r(x)/p(x) are finite so  -1 is regular 
 x------> -1                        x------> -1
singular point

case 2
a=1
lim (x-1)) q(x)/p(x)=lim (x-1) 3(x+1)/x²-1=lim3(x+1)/x+1= 3
x------> 1                  x------> 1                    x------> 1
lim (x-1))²  r(x)/p(x)= lim(x-1)²/x²-1= =0
x------> 1                    x------> 1

1 is also a regular singular point


5 0
3 years ago
Find the value of x. Round your answer to the nearest tenth. Will mark brainlist !
mars1129 [50]

Answer:

answer is 17.5

Step-by-step explanation:

use formula a^2 + b^2 = c^2 (letters represent each side of the triangle)

9^2 + 15^2 = 306

306 = x^2. find the square root of 306 to find x

√306 = 17.4928557

rounded it to the nearest 10th

17.5

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Answer:

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Step-by-step explanation:

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