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aniked [119]
3 years ago
7

Determine the singular points of the following differential equation and classify each singular point as regular or irregular.

Mathematics
1 answer:
anygoal [31]3 years ago
5 0
Let be
p(x)=<span>(x^{2} -1
q(x)=</span><span>3(x+1)
r(x)=1
the three coefficients of the equation
a is a singular point of the equation if   lim p(x) =0
                                                              x------>a 
so let's find a
</span> lim p(x) = lim x²-1=a²-1=0
  x------>a    x------>a 
a²-1=0 implies  a=+ or -1

so the sigular points are a= -1 or a=1

case 1
for a= -1
lim (x-(-1)) q(x)/p(x)=lim (x+1) 3(x+1)/x²-1=lim3(x+1)/x-1= 0/-2=0
x------> -1                  x------> -1                    x------> -1
lim (x-(-1))²  r(x)/p(x)= lim(x+1)²/x²-1= 0/-2=0
x------> -1                    x------> -1

lim (x-(-1)) q(x)/p(x) and lim (x-(-1))²  r(x)/p(x) are finite so  -1 is regular 
 x------> -1                        x------> -1
singular point

case 2
a=1
lim (x-1)) q(x)/p(x)=lim (x-1) 3(x+1)/x²-1=lim3(x+1)/x+1= 3
x------> 1                  x------> 1                    x------> 1
lim (x-1))²  r(x)/p(x)= lim(x-1)²/x²-1= =0
x------> 1                    x------> 1

1 is also a regular singular point


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Step-by-step explanation:

We use

a ^{2}  -  \times ^{2}  = (a -  \times )(a +  \times )

Now we have

\frac{ { \times }^{2} }{9}  - 64 = ( \frac{ \times }{3} ) ^{2}  -  {8}^{2}  \\  = ( \frac{ \times }{3}  - 8)( \frac{ \times }{3}  + 8)

Hope that useful for you

5 0
3 years ago
Simplify 2^2[4+(3-6)^2]-13
HACTEHA [7]

Answer:

It's 19.

Step-by-step explanation:

Use order of operations (PEMDAS):

2^2[4+(3-6)^2]-13

Parentheses first:

= 2^2[4 + (-2)^2] - 13

= 2^2 ( 4 + 4) - 13

=  2^2 * 8 - 13

Now work out the exponent:

= 4*8 - 13

Now the multiplication:

= 32 - 13

= 19.

8 0
3 years ago
4 is what percent of 20
neonofarm [45]
20%
Finding percentage u have to
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3 0
2 years ago
A 3-gallon tub of ice cream yields about 90 scoops of ice cream. There are roughly 3785 cubic centimeters in 1 gallon. Determine
ASHA 777 [7]

Answer:

The radius of the scoop is r = 3.1 cm

Step-by-step explanation:

Since 3 gallons yields 90 scoops, and 1 gallon = 3785 cm³.

3 gallons = 3 × 3785 cm³ =  11355 cm³

So we have 11355 cm³ in 3 gallons which is also the volume of 90 scoops.

Since 90 scoops = 11355 cm³, then

1 scoop = 11355 cm³/90 = 126.2 cm³

Now, if each scoop is a sphere, the volume is given by V = 4πr³/3 where r is the radius of the scoop. Since we need to find the radius of the scoop, r, making r subject of the formula, we have

r = ∛(3V/4π)

Substituting V = 126.2 cm³, we have

r = ∛(3× 126.2 cm³/4π)

= ∛(378.6 cm³/12.57)

= ∛30.13 cm³

= 3.1 cm

So, the radius of the scoop is r = 3.1 cm

5 0
3 years ago
F(n)=x2+1<br> g(n)=2x-5<br> Find f(n)-g(n)
Artist 52 [7]
Answer:

x^2 - 2x + 6

Explanation:

(x^2 + 1) - (2x - 5)
x^2 + 1 - 2x + 5
x^2 - 2x + 6
8 0
3 years ago
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