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mihalych1998 [28]
4 years ago
11

Can anyone find the x and y intercepts for this equation?

Mathematics
1 answer:
ASHA 777 [7]4 years ago
7 0
<span><u>1/3x - 1/2y = 1</u>

At the 'x' intercept, y=0 , and the equation is    1/3 x = 1

Multiply each side by 3 :            <em>x = 3 </em> <== the x-intercept


At the 'y' intercept,  x=0, and the equation is  -1/2 y = 1

Multiply each side by  2 :            - y = 2

Multiply each side by  -1 :            <em> y = -2  </em>  <== the y-intercept
</span>
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Write the two conditional statements that make up the following biconditional.
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The correct answer is A. <span>If I drink juice, then it is breakfast time.
If it is breakfast time, then I drink juice.

This answer is an if-and-only-if conditional statement.
The other options are not.</span>
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3x3 + 9x2 - 15x<br> What's the answer
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Answer:

3x(x^2+3x-5) - factorised

Step-by-step explanation:

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The probability that a person in the United States has type B​+ blood is 10%. Four un-related people in the United States are se
marysya [2.9K]

Answer:

a. 0.0001

b. 0.6561

c. 0.3439

d. B. The event in part​ (a) is unusual because its probability is less than or equal to 0.05.

Step-by-step explanation:

a. # We are given that the probability that a person in the United States has Type B+ blood = 0.10. Also we are told that four unrelated people in the United States are selected at random.

#We have to find here the probability that all four have type B+ blood.

Since the events are independent, we have :

Probability that all four have B+ blood  = 0.10 x 0.10x 0.10x0.10

                                                                                       = 0.0001

Therefore, the probability that all four have type B+ blood is 0.0001

b. We have to find the probability that none have B+ blood. Using the complementary law of probability we have:

Probability that blood type is not B+ = 1 - 0.10= 0.90                                                                        

Therefore, the probability that none have B+ blood

= 0.90 x 0.90 x 0.90x0.90=0.6561

Therefore, the probability that none have B+ blood is 0.6561

c. We have to find the probability that at least one of the four have B+ blood.

#The probability that at least one of the four have B+ blood = 1 -  Probability that none have B+ blood type

=1-0.6561=0.3439

Therefore,the probability that at least one of the four has type B+ blood is 0.3439

d. An event is considered unusual if the probability of the event is small or less than 0.05 . We note that event a is the only small probabilty and is less than 0.05.

-a is thus considered unusual(the rest are all usual events)

                                                                                                                 

6 0
3 years ago
Which expression is the factored form of x2 – 7x 10? (x 3)(x 4) (x – 3)(x – 4) (x – 2)(x – 5) (x 2)(x 5)
alexandr402 [8]

The expression x^2 -7x + 10 can be written in factored form as given by Option C: (x-2)(x-5)

<h3>How to find the factors of a quadratic expression?</h3>

If the given quadratic expression is of the form ax^2 + bx + c

then its factored form is obtained by two numbers alpha( α ) and beta( β) such that:

b = \alpha + \beta \\ ac =\alpha \times \beta

Then writing b in terms of alpha and beta would help us getting common factors out.

Sometimes, it is not possible to find factors easily, so using the quadratic equation formula can help out without any trial and error.

For this case, we're provided the expression:

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we can write -7 as sum of -5 and -2. Thus, we get:

x^2 -7x + 10 = x^2 -5x - 2x + 10 = x(x-5+ -2(x-5) = (x-2)(x-5)

Thus, the expression x^2 -7x + 10 can be written in factored form as given by Option C: (x-2)(x-5)

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brainly.com/question/26675692

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