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mihalych1998 [28]
4 years ago
11

Can anyone find the x and y intercepts for this equation?

Mathematics
1 answer:
ASHA 777 [7]4 years ago
7 0
<span><u>1/3x - 1/2y = 1</u>

At the 'x' intercept, y=0 , and the equation is    1/3 x = 1

Multiply each side by 3 :            <em>x = 3 </em> <== the x-intercept


At the 'y' intercept,  x=0, and the equation is  -1/2 y = 1

Multiply each side by  2 :            - y = 2

Multiply each side by  -1 :            <em> y = -2  </em>  <== the y-intercept
</span>
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Someone please help quickly.......
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Answer:

(2,-6)

Step-by-step explanation:

The solution set is any point to the left of the line. To find the solution set, test a point like (0,0).

3(0) + 4(0) \leq -1\\0\leq -1\\False

This means (0,0) is not in the solution set. The solution set is the region to the left of the line. Any point in this area will be a solution.

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4 years ago
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<u>Step-by-step explanation:</u>

Here we have to find the derivative of ln(lnx^3) , Let's find out:

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⇒ \frac{1}{u} (\frac{d(ln(x^3))}{dx} )

Let x^3=v

⇒ \frac{1}{u} (\frac{d(ln(v))}{dx} )

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⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )            

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Putting value of u & v we get:

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Therefore , the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

6 0
4 years ago
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