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3 years ago

14

HELPPPPP MEEEEE BROOOOSSSSS

1 answer:

shutvik [7]3 years ago

4 0

Answer:

where is the question bro

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What are the explicit equation and domain for a geometric sequence with a first term of 4 and a second term of −12?

Lerok [7]

$a_1=4;\ a_2=-12\\\\r=\dfrac{a_2}{a_1}\to r=\dfrac{-12}{4}=-3$

The formula of a geometric sequence:

$a_n=a_1\cdot r^{n-1}$

substitute

$a_n=4\cdot(-3)^{n-1}$

$The\ domain:\ \text{all integers where}\ n\geq1$

Answer: $\boxed{a_n=4(-3)^{n-1};\ \text{all integers where}\ n\geq1}$

4 0

3 years ago

65 POINTS PLEASE HELP

miskamm [114]

Answer:

1

= -----------

6(x + 7)

Step-by-step explanation:

3x - 21 x^2 - 49

----------- ÷ -------------

18x - 18 x - 1

3x - 21 x - 1

----------- × -------------

18x - 18 x^2 - 49

Factor the top left:

3x - 21 = 3(x - 7)

Factor the bottom left:

18x - 18 = 18(x - 1)

Factor the new bottom right:

x^2 - 49 = (x + 7)(x - 7)

Multiply and simplify the faction:

3(x - 7) x - 1

----------- × -----------------

18(x - 1) (x + 7)(x - 7)

1

= -------------

6(x + 7)

6 0

3 years ago

Read 2 more answers

Tan 45°. tan² 30° tan 60° <br>slove it

makvit [3.9K]

Answer:

$\frac{\sqrt{3} }{3} or \frac{1}{\sqrt{3} }$

Step-by-step explanation:

We can break the problem into three parts,

tan45 = sin(45)/cos(45)= $\frac{\frac{\sqrt{2}}{2} }{\frac{\sqrt{2}}{2} } =1$

$tan^{2}30 =(tan30))^{2}=(sin30/cos30)^2=((1/2)/(\sqrt{3}/2))^2 =(1/\sqrt{3})^2$

$tan60=sin60/cos60=\frac{\sqrt{3}/2 }{1/2} =\sqrt{3}$

Then, $tan45*tan^230*tan60=1*(1/sqrt(3))^2*sqrt(3)=1/sqrt(3)=sqrt(3)/3$

Therefore, the solution is sqrt(3)/3

4 0

2 years ago

uysha [10]

24=7/8g
divided by 7/8 divided by 7/8
24*8/7=g
192/7=g
27 3/7=g
The answer is D. 27 3/7

7 0

3 years ago

Anna saves 5/8 of her money. What percent of her money does Anna save?

scoray [572]

the amnwer is 1.6. all you do is 8 dived by 5

6 0

3 years ago

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