Answer:
(a)
Number of cars with defective turn signals = 65
Number of cars with no defective turn signals = 410 - 65 = 345
<u>Required probability:</u>
- P = 345/410*100% ≈ 84.15%
(b)
Number of cars with defects = 65 + 35 = 100
Number of cars with no defects = 410 - 100 = 310
<u>Required probability:</u>
- P = 310/410*100% ≈ 75.61%
We are trying to represent the change in position of a bird flying down 7 ft to the ground.
Often, for the y axis- up is positive and down is negative.
Change in position is displacement- how far it was from the starting point
( different from distance which is how far is traveled
ex. doubling back would have distance they traveled some distance while the displacement is 0 because they are back to where they started).
The bird is going down 7 ft from where it originally was, which can be represented by
Bird's displacement = -7 ft
A) because when they are equal it means that their y has the same value, which means their intersection point.
B) You should take all integers from (-2, 2) which are: -2, -1, 0, 1, 2 and put them one by one in the example:
x = -2
y1 = 4^-(-2) = 4^2 = 16
y2 = 2^(-(-2) + 1) = 2^(2+1) = 2^3 = 8
y1 ≠ y2 => so x=-2 isn't our answer
-------------------------------------------------------
x = -1
y1 = 4^-(-1) = 4^1 = 4
y2 = 2^(-(-1) + 1) = 2^(1+1) = 2^2 = 4
y1 = y2 => so our answer will be x = -1
-------------------------------------------------------
x = 0
y1 = 4^-(0) = 4^0 = 1
y2 = 2^(-(0) + 1) = 2^(0+1) = 2^1 = 2
y1 ≠ y2 => so x=0 isn't our answer
--------------------------------------------------------------
x = 1
y1 = 4^-(1) = 4^(-1) = 1/4
y2 = 2^(-(1) + 1) = 2^(-1+1) = 2^0 = 1
y1 ≠ y2 => so x=1 isn't our answer
--------------------------------------------------------------
x = 2
y1 = 4^-(2) = 4^(-2) = 1/16
y2 = 2^(-(2) + 1) = 2^(-2+1) = 2^(-1) = 1/2
y1 ≠ y2 => so x=2 isn't our answer
Which means that our final answer is: x=-1
C) You should draw both graphics, and their intersection point (x) will be the answer.
I hope it helped.
Step-by-step explanation:
<em>Answer</em><em> </em><em>1</em><em> </em><em>to find the base</em><em> to apply the Pythagoras </em><em>theorem.</em><em>.</em><em>of</em><em> </em><em>finding</em><em> </em><em>length</em><em>.</em><em>.</em>
<em>Hypotenuse²</em><em>=</em><em> </em><em>Base²</em><em>+</em><em> </em><em>Height</em><em>²</em>
<em>So,</em>
<em>(</em><em>H</em><em>)</em><em>²</em><em>=</em><em> </em><em>(</em><em>B)</em><em>²</em><em>+</em><em>(</em><em>H)</em><em>²</em>
<em>1</em><em>2</em><em>²</em><em>=</em><em> </em><em>8</em><em>²</em><em>+</em><em>y²</em>
<em>1</em><em>4</em><em>4</em><em>-</em><em>6</em><em>4</em><em>=</em><em>y²</em>
<em>8</em><em>0</em><em>=</em><em>y²</em>
<em>√</em><em>8</em><em>0</em><em>=</em><em> </em><em>y</em>
<em>√</em><em>2</em><em>×</em><em>2</em><em>×</em><em>2</em><em>×</em><em>2</em><em>×</em><em>5</em><em>=</em><em> </em><em>y</em>
<em>2</em><em>×</em><em>2</em><em>√</em><em>5</em><em>=</em><em> </em><em>y</em><em> </em><em> </em><em>(</em><em> </em><em>take</em><em> </em><em>one</em><em> </em><em>2</em><em> </em><em>from</em><em> </em><em>each</em><em> </em><em>pair)</em>
<em>4</em><em>√</em><em>5</em><em>=</em><em> </em><em>y</em>
<em>hope</em><em> it</em><em> helps</em><em>.</em><em>.</em><em>.</em>
Answer:
Step-by-step explanation:
m÷350 = 299
m = 299×350 = 104,650