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Lesechka [4]
2 years ago
9

If x ≠ 2y, then eq1a 2(x-2y) 2y-x 1 0 -2

Mathematics
1 answer:
lesya692 [45]2 years ago
8 0
The answer is 0 because they’re the same
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Sylvia has a total of 16 trading cards: 8 superhero cards, 4 princess cards,2 villain cards, and 2 wildlife cards. what is the r
balu736 [363]
There as 16 cards, 2 of which are wildlife cards, so the ratio is 16 : 2. We can simplify it by dividing both sides by 2, so we'll get the ratio of 8 : 1.

I hope this helps! :)


5 0
3 years ago
Three students failed their last test. If 12% of the class failed, how many students are in the class?
stellarik [79]

Answer:

There are 25 students in the class.

Step-by-step explanation:

Let x be the number of students in the class

12% failed and the number of students is 3

x*12% = 3

x*.12 = 3

Divide each side by .12

x * .12 /.12 = 3/.12

x =25

There are 25 students in the class

3 0
2 years ago
Read 2 more answers
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

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5 0
1 year ago
Write a equation for (-6, -3)
Vlad [161]

<u>Answer</u>:

equation: y = x/2

<u>Explanation</u>:

let the points be  (-6, -3) ,  ( 0, 0)

slope: \frac{y2-y1}{x2-x1}

         : \frac{0--3}{0--6}

         : \frac{1}{2}

Equation using:

y - y1 = m ( x - x1 )

y - - 3 = 1/2( x - - 6 )

y + 3 = x/2 + 3

y\\ = \frac{x}{2}

5 0
2 years ago
What is 15% of 60? create a model to prove your answer. in equivalent fractions
amid [387]
15% of the number 60 is 9
6 0
3 years ago
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