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bagirrra123 [75]
3 years ago
9

Priya bought these ítems at the grocery store. Find each unit price.

Mathematics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

Eggs: 25 cents ea.

Pounds of peanuts: $2.50 ea.

Rolls of toilet paper: 50 cents ea.

Apples: 35 cents ea.

Step-by-step explanation:

This is assuming you meant $3 for 12 eggs, and $2 for 4 rolls of toilet paper.

For the eggs, I did 3 / 12 = .25 (aka 25 cents);

For the peanuts: 7.50 / 3 = $2.50;

For the toilet paper: 2 / 4 = .50 (aka 50 cents);

For the apples: 3.50 / 10 = .35 (aka 35 cents).

Hope this helped ~

:D

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For this case we must find the value of the variable of the following equation:

\frac {2} {3} x + 4 = \frac {1} {2} x + 5

Subtracting \frac {1} {2} x from both sides:

\frac {2} {3} x- \frac {1} {2} x + 4 = 5\\\frac {4-3} {6} x + 4 = 5\\\frac {1} {6} x + 4 = 5

Subtracting 4 from both sides:

\frac {1} {6} {x} = 5-4\\\frac {1} {6} x = 1

Multiplying by 6 on both sides:

x = 6 * 1\\x = 6

Answer:

x = 6

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3 years ago
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if the breadth of rectangle in one third of it's length and perimeter is 80 cm,find the length and breadth of rectangle​
Serhud [2]
Length=x
Breadth=1/3x
(x+1/3x)×2=80
4/3x×2=80
8/3x=80
x=30
Length=30
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7 0
2 years ago
What is the answer to -6(4r+2)+5
RideAnS [48]

Answer:

-24r - 7

Step-by-step explanation:

-6(4r + 2) + 5

-24r - 12 + 5

-24r - 7

Best of Luck!

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3 years ago
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2617 and standard deviation
Eduardwww [97]

Answer:

a) N(2617, 586)

b) 0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c) 0.4013 = 40.13% of the customers consume over 2764 calories

d) 3981 calories.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 2617, \sigma = 586

a. What is the distribution of X?

Here we first place the mean, then the standard deviation.

N(2617, 586)

b. Find the probability that the customer consumes less than 2409 calories.

This is the pvalue of Z when X = 2409. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2409 - 2617}{586}

Z = -0.355

Z = -0.355 has a pvalue of 0.3613

0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c. What proportion of the customers consume over 2764 calories?

This is 1 subtracted by the pvalue of Z when X = 2764. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2764 - 2617}{586}

Z = 0.25

Z = 0.25 has a pvalue of 0.5987

1 - 0.5987 = 0.4013

0.4013 = 40.13% of the customers consume over 2764 calories

d. The Piggy award will given out to the 1% of customers who consume the most calories. What is the fewest number of calories a person must consume to receive the Piggy award?

Top 1%, so the 100-1 = 99th percentile.

The 99th percentile is the value of X when Z has a pvalue of 0.99. So it is X when Z = 2.327. So

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 2617}{586}

X - 2617 = 2.327*586

X = 3980.6

Rounding to the nearest calorie, 3981 calories.

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Answer: 40

Step-by-step explanation:

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