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lozanna [386]
3 years ago
7

Uncle Jason is twice as old as his nephew Ralph, and 10 years ago he was three times as old as Ralph. Find their present ages.

Mathematics
1 answer:
cluponka [151]3 years ago
7 0

Answer:

40 and 20

Step-by-step explanation:

  • Uncle Jason's age = x
  • Nephew Ralph age = y
<h3>Solution</h3>

<u>Age now:</u>

  • x= 2y

<u>Age 10 years ago: </u>

  • x- 10 = 3(y-10)

<u>Substituting x in the second equation:</u>

  • 2y - 10 = 3y - 30
  • 3y - 2y = 30 -10
  • y = 20

<u>Then, finding x:</u>

  • x= 2y
  • x= 2*20
  • x= 40

<u>Answer:</u> Uncle Jason is 40 and nephew Ralph is 20 years old

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X=the missing value

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so the formula is

25+x/2=31.5
use algebra to solve
25+x=63
x=63-25
x= 38

Therefore, the missing value is 38.

Hope this helped. Let me know if you have any further questions:)
6 0
3 years ago
Write your answer with no spaces and any fraction with “/“
Archy [21]

Answer:

The slope is 1/2

Step-by-step explanation:

Hi!

Disclaimer: Just for this response, I'm going to write it the same way you write a fraction out on paper just so it's easier to see.

First, you plot the two coordinates on the graph:

(0,0) and (2,1)

The formula for slope is \frac{y1 - y2}{x1 - x2}

Now we plug in numbers accordingly:

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Let me know if you have any questions

6 0
3 years ago
What is the range of the given function?
Travka [436]

Answer:

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Step-by-step explanation:

range is y values

4 0
3 years ago
Read 2 more answers
Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7
Gre4nikov [31]
<h2>The product of the rational expressions\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}.</h2>

Step-by-step explanation:

We have,

\dfrac{7x}{x-4}.\dfrac{x}{x+7}

To find, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = ?

∴ \dfrac{7x}{x-4}.\dfrac{x}{x+7}

= \dfrac{7x.x}{(x-4)(x+7)}

= \dfrac{7x^2}{(x(x+7)-4(x+7)}

= \dfrac{7x^2}{x^2+7x-4x-28}

= \dfrac{7x^2}{x^2+3x-28}

Thus, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}.

7 0
3 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
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