Ok, here we go. Pay attention. The formula for the arc length is
. That means that to use that formula we have to find the derivative of the function and square it. Our function is y = 4x-5, so y'=4. Our formula now, filled in accordingly, is
(that 1 is supposed to be negative; not sure if it is til I post the final answer). After the simplification we have the integral from -1 to 2 of
. Integrating that we have
from -1 to 2.
gives us
. Now we need to do the distance formula with this. But we need 2 coordinates for that. Our bounds are x=-1 and x=2. We will fill those x values in to the function and solve for y. When x = -1, y=4(-1)-5 and y = -9. So the point is (-1, -9). Doing the same with x = 2, y=4(2)-5 and y = 3. So the point is (2, 3). Use those in the distance formula accordingly:
which simplifies to
. The square root of 153 can be simplified into the square root of 9*17. Pulling out the perfect square of 9 as a 3 leaves us with
. And there you go!
Answer:
Would 50 divided by 40 work?
Step-by-step explanation:
Number 2 is 20 number 3 is 11
Oh Foxy, Foxy, how totally debilitated you must be ! Try to relax. Nobody
enjoys a painful brain, and believe me, this problem is not worth it.
Let me put it to you this way: What if the problem said . . .
-- Demarcus has $8 more than his sister.
-- His sister has $4.
-- How much money ' M ' does Demarcus have ?
If your brain didn't hurt, you could quickly solve this right in there.
You would know that Demarcus' money ' M ' = 8 + 4 .
That's <em>almost </em>exactly what the problem <em>does</em> say.
Except it doesn't say he has "$8 more than his sister",
it says he has "at least" that much.
So you know that ' M ' is not exactly = 8 + 4, but that's the <u>least</u> it could be.
The actual amount of ' M ' is <u>more</u> than that.
Surely you can handle it from here, even with half of your brain
tied behind your back.
Take a good hard look at ' A ', and then go lie down.
Step-by-step explanation:
f(x)=3x−2 so when the variable x is replace with an actual value ( − 1 ) we get f(−1)=3(−1)−2
=−3−2
=−5
