Answer:
10=y/11-13
We move all terms to the left:
-10-(y/11-13)=0
-y/11+13-10=0
We multiply all the terms by the denominator
-y+13*11-10*11=0
We add all the numbers together, and all the variables
-1y+33=0
We move all terms containing y to the left, all other terms to the right
-y=-33
y=-33/-1
y=+33
Answer:
25π-24
Step-by-step explanation:
from the figure,
radius of the circle(r)=diameter of the circle(d)/2
=10/2
=5
Area of the circle(A)=πr^2
=π5^2
=25π
Again,
base of the right angle triangle(b)=6
perpendicular of right angle triangle(p)=8
we also know,
the area of right angle triangle = 1/2*base*height
=1/2*6*8
=1/2*48
=48/2
=24
Now, Area of the shaded region=Area of circle - Area of right angle triangle (given in the figure)
Area of shaded region= 25π -24
Answer:
The surface of the prism is 84m²
Step-by-step explanation:
You have 4 figures here (two the same triangles)
you need to determine the surface of each and then sum it to one. This will be your final surface.
rectangles:
3*6= 18m²
5*6 = 30m²
4*6 = 24m²
triangles:
You need to determine the square of the triangles from the Heron's formula.
Heron's formula states that the area of a triangle whose sides have lengths a, b, and c is
,
where s is the semi-perimeter of the triangle; that is,
.
So the permimeter of the triangle is
2p=4+5+3 = 12m
p = 6m
![S = \sqrt{p*(p-a)*(p-b)*(p-c)} = \sqrt{6*(6-3)*(6-4)*(6-5)} = \sqrt{6*3*2*1} =\sqrt{36} =6[m^{2} ]](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%7Bp%2A%28p-a%29%2A%28p-b%29%2A%28p-c%29%7D%20%20%3D%20%5Csqrt%7B6%2A%286-3%29%2A%286-4%29%2A%286-5%29%7D%20%20%3D%20%5Csqrt%7B6%2A3%2A2%2A1%7D%20%3D%5Csqrt%7B36%7D%20%3D6%5Bm%5E%7B2%7D%20%5D)
So the surface of the prism is a total sum of all surfaces:
P = 18m²+30m²+ 24m²+2*6m² = 84m²
9514 1404 393
Answer:
10x -5 +5h
Step-by-step explanation:
Use the function definition with the given arguments.

Answer:
C
10% = (10÷100=1÷10)=2÷20=.10