Answer:
With my predictions it is 2/11 hope it helps
Answer:
solo suma todos los valores x+4(3)+(x+x)
en el segundo x+5(2)+x+3(2)
en el tercero x-3+(2x+5)+(2x+5)
y en el cuarto x(3)+(x+4)
Umm 4.67 is and Avila so6.779 is going to bet that answer
Answer:
Step-by-step explanation:
Left Hand Side
Change to sin(theta) and cos(theta)
csc(theta) = 1/sin(theta)
cot(theta) = cos(theta)/sin(theta)
1/sin(theta) - cos(theta)/sin(theta) Put over Sin(theta) Common denominator
[1 - cos(theta)] / sin(theta) Multiply numerator and denominator by 1 + cos(theta)
(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))
(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)
sin^2(theta) / (sin(theta)* ( 1 + cos(theta)
sin(theta) / (1 + cos(theta) )
Right hand Side.
See Above.
Range is the highest value minus the lowest value
