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matrenka [14]
3 years ago
11

Is -5 a solution to the equation 6x + 5 + 8 + 2x ?

Mathematics
1 answer:
Karolina [17]3 years ago
5 0

Answer:

Nope the answer would be -6.5

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I'm stuck on this. will give brainliest to whoever answers.​
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there will be 60 ounces left

Step-by-step explanation:

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1 One number is 2 more than 3 times another number.
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x=3y+2

14-y=3y+2

12=4y

3=y ANSWER 1: One of the numbers is 3.

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x=14-y=14-3=11 ANSWER 2: The other number is 11.

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Evaluate 1x + y, for x = 8 and y=-15.<br> 7 <br> -7<br> 23<br> -23
statuscvo [17]

Answer:

B) -7

Step-by-step explanation:

x+y

8+(-15)=8-15=-7

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Which graph shows the solution to the following system?
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Determine if the described set is a subspace. Assume a, b, and c are real numbers. The subset of R3 consisting of vectors of the
Arte-miy333 [17]

This question is incomplete, the complete question is;

Determine if the described set is a subspace. Assume a, b, and c are real numbers.

The subset of R³ consisting of vectors of the form \left[\begin{array}{ccc}a\\b\\c\end{array}\right] , where abc = 0

  • The set is a subspace
  • The set is not a subspace

Answer:

Therefore; The set is not a subspace

Step-by-step explanation:

Given the data the question;

the subset R³;

S = {  \left[\begin{array}{ccc}a\\b\\c\end{array}\right] , where abc = 0 }

we know that a subset of R³ is a subspace if it stratifies the following properties;

  1. it contains additive identity
  2. it is closed under addition
  3. it is closed under scales multiplication

Looking at the properties, we can say that it is not a subspace

As;

         u = \left[\begin{array}{ccc}1\\1\\0\end{array}\right] ∈ S       and v = \left[\begin{array}{ccc}0\\1\\1\end{array}\right]  ∈ S

As    1×1×0=0                          0×1×1=0

But   u+v = \left[\begin{array}{ccc}1+0\\1+1\\0+1\end{array}\right] = \left[\begin{array}{ccc}1\\2\\1\end{array}\right]  ∉  S     as 1×2×1 ≠ 0

Hence, it is not closed under addition.

Therefore; The set is not a subspace

4 0
3 years ago
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