The maximum height is yo<span> = 0</span>
When the projectile is at its maximum height <span> v</span>y = 0.
Note that the maximum height is determined solely by the initial velocity in the y direction and the acceleration due to gravity. :)
Answer:
L=3w+2...L+w=40... 4w+2=40...w=3/5 and L=30/5
I believe the correct option is C after I checked it over and over again...
